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化简log2(1+2^0.5+3^0.5)+ log2(1+2^0.5-3^0.5)

来源：学生作业帮 编辑：拍题作业网作业帮 分类：数学作业 时间：2024/05/10 03:01:34
化简log2(1+2^0.5+3^0.5)+ log2(1+2^0.5-3^0.5)
原式=log2[(1+√2+√3)(1+√2-√3)]
(1+√2+√3)(1+√2-√3)
=(1+√2)^2-(√3)^2
=1+2√2+2-3
=2√2
=2*2^(1/2)
=2^(3/2)
所以原式=log2[2^(3/2)]=3/2
2^log2 (3) × log2 (1/8) + 2lg3 不等式log2(2x+3)>log2(x+1)的解集是 log2 (x + 3) + log2(x + 2) = 1 根号下[(log2^3)^2-4log2^3+4]+log2^(1/3) log2（√1/48）+log2 12-1/2log2 （24）-1/3 log2 3乘以log2 3等于2log2 (log2 9)/(log2 8) = 2/3(log2 3) log2 SQR(7/48)+log2 12 -1/2log2 48 log2 SQR(7/48)+log2 12 -1/2log2 42 2∧log2 1/3等于多少 2^(log2^(-3))= （1/2)的log2底3为什么等于2的log2底1/3