Compound Relative molecular mass

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Compound Relative molecular mass
CH3CH2OH 46
CH3CH2OCH3 80
CH3CH2CO2CH3 88
C6H12O6 180
When 1 g of each these compunds undergoes complete combustion,which one will produce the greatest number of moles of carbon dioxide?
难道真的要把公式全列出吗?应该有更快的方法吧?

问题是
1g上述物质完全燃烧,那个产生的二氧化碳比较多
显然分子量/碳原子个数最小的是最佳答案
23 23.3 22 30
选最后一个
再问：可答案是第二个......
再答：最小的是第三个答案是第二个吗？
再问：是呀~
再答：第二个分子量给错了，是60，这样他最小了
再问：可我想问一下为什麼碳原子个数最小反而给出最多二氧化碳?
再答：是分子量与碳原子个数的比值最小二氧化碳的生成量=1g/物质分子量*碳原子个数

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