log2(6)*log3(6)-[log2(3)+log3(2)]的值

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/06/01 12:01:04

log2(6)*log3(6)-[log2(3)+log3(2)]
=lg6/lg2xlg6/lg3-(lg3/lg2+lg2/lg3)
=(lg6)^2/lg2lg3-[(lg3)^2+(lg2)^2]/lg2lg3
=(lg2+lg3)^2/lg2lg3-[(lg3)^2+(lg2)^2]/lg2lg3
=[(lg2)^2+2lg2lg3+(lg3)^2]/lg2lg3-[(lg3)^2+(lg2)^2]/lg2lg3
=2lg2lg3/lg2lg3
=2

log2(3)+log3(5)+log3(2)=? 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15 (log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7) lg2+lg5-log2(3)乘log3(2) 求下列各式的值 1）log2 6+log2 3 2)lg5+lg2 3)log5 3+log5 三分之一 4）log3 log2(20)-log2(5)+2log3(2)×log4(3) (log3^4+log5^2)(log2^9+log2^根号3) log2 3×log3 7=log2 7 3/2,log3^5,log2^3的大小关系是 log3(5),log2(3),2/3的大小关系 log3 2等于log2 3的x次方我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log