化简cosα · cos2α · cos4α .cos2^(n-1)α (n∈N*)
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化简cosα · cos2α · cos4α .cos2^(n-1)α (n∈N*)
cosa*cos2a*cos4a*.*cos2^(n-1)a
=sina*cosa*cos2a*....*cos2^(n-1)a/sina
=1/2sin2a*cos2a*cos4* ...* cos2^(n-1)a/sina
=1/4sin4a*cos4a*...*cos2^(n-1)a/sina
=1/8sin8a*...*cos2^(n-1)a/sina
=1/2^(n-1)sin2^(n-1)*cos2^(n-1)a/sina
=1/2^n*sin2^na/sina
=sina*cosa*cos2a*....*cos2^(n-1)a/sina
=1/2sin2a*cos2a*cos4* ...* cos2^(n-1)a/sina
=1/4sin4a*cos4a*...*cos2^(n-1)a/sina
=1/8sin8a*...*cos2^(n-1)a/sina
=1/2^(n-1)sin2^(n-1)*cos2^(n-1)a/sina
=1/2^n*sin2^na/sina
[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=?
化简:cos2分之x乘以cos4分之x.cos2的n次方分之x=?
化简:cos2α-cos2β/cosα-cosβ
化简cos4α+sin2αcos2α+sin2α
证明:(1-cos4α)/sin4α*cos2α/(1+cos2α)=tanα
化简:sinαcosαcos2α
化简:cosαcos2αcos3α
sin4α-cos4α=sin2α-cos2α求证
证明sin4α-cos4α=sin2α-cos2α
已知cos2α=1/4,则cos4α+sin4α+sin2αcos2α的值为?
化简sin²α·sin²β+cos²αcos²β-1/2cos2α·cos2β
化简(sinα-cosα)^2-1/-cos2α