[log2(x)]^2+(a+1/a)log1/2(x)+1
[log2(x)]^2+(a+1/a)log1/2(x)+1
解不等式log1/2^(x+1) +log2^[(1/(6-x)] 大于log1/2^12
关于x的方程log√2(x)+log1/2(x-1)=log2(a)有解,求实数a的取值范围
解不等式log2(x+1)+log1/4(x-1)〉log4(2x-1)
求函数f(x)=log2/5^(x+1)-log1/5^[(x+1)^2]
log2(2^x-1)log1/2[2^(x+1)-2]0的取值范围?
求不等式log1/2(x+1)≥log2(2x+1)的解集
求函数y=log1/2(1-3^x)-log2(3^x+1/3)的最小值
解不等式log1/2(3-x)>=log2(x+3)-1
求函数f(x)=log2(2x)*log1/4(x),x∈〔1/2,8〕的值域
若-3≤log1/2x≤-1/2,求f(x)=(log2 x/2)*(log2 x/4)的最大值和最小值
已知-3小于等于log1/2 x大于等于-1/2,求函数f(x)=(log2 x/2)(log2 x/4)的最大值和最小