(11-X)*5=43-X 55-5X=43-X 4X=12 X=3

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英语翻译ProductName:S-217 ACTUAL:120(W)X55(D)X85(H) PACKAGE:123(

ProductName:S-217产品名称:S-217ACTUAL:120(W)X55(D)X85(H)实物:120(宽)x55(厚)x85(高)PACKAGE:123(L)X65(W)X10.5(H

(2x-1)/(x-1)(x-2)=(x-5)/(x-2)(x-3) x/2x^2-11x-21=(x+7)/x^2-1

这是两道题吗?1、两边同时乘(x-1)(x-2)(x-3)答案是x1=-1,x2=22、分母因式分解分别为(x-7)(2x+3)和(x-5)(x-7)然后同时乘(x-5)(x-7)(2x+3)答案是x

解方程:x/(2x-11x-21)=(x-5)/(x2-12x+35) 求x

x/(2x^2-11x-21)=(x+7)/(x^2-12x+35)x/(2x+3)(x-7)=(x+7)/(x-5)(x-7)x/(2x+3)=(x+7)/(x-5)x(x-5)=(x+7)(2x+

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

解高次方程x^6-63x^5-5x^3-11x^2-43x=101怎么解呀?

编程解得x有6个解!x=-163.001306531085730889402404456827.90484104926952632108635925206247+.774353265124758763

x的平方+5x+7=3x+11

x²+2x=4x²+2x+1=4+1(x+1)²=5x+1=±√5x=-1-√5,x=-1+√5

解方程:5x(x+7)(x+4)=5x(x的平方+11x)

【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x

已知2x*x+x-5=0,求代数式6x*x*x+7x*x-13x+11的值

6x^3+7x^2-13x+11=6x^3+3x^2-15x+4x^2+2x-10+21=3x(2x*x+x-5)+2(2x*x+x-5)+21=3x*0+2*0+21=21

5x(x+7)(x+4)=5x(x^2+11X)

5x(x+7)(x+4)=5x(x^2+11X)5x^3+55x^2+140x=5x^3+55x^2140x=0x=0

解方程x(2x-3)+3x+3x(x-2)=5x(x-4)+11

x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x

7x-11=5x+27

7x-11=5x+277x-5x=27-112x=16x=8

55x55/56=?的简便算法?

55×55/56=(56-1)×55/56=56×55/56-1×55/56=55-55/56=54又1/56

13X-4(2X+5)=2(X+11)

13x-8x-20=2x+223x=42x=14

x+4x+8=4x+11 x(2x-4)=5-8x解方程急!

再问:请给详细过程。再答:

先观察下列各式,(x+5)(x+6)=x²+11x+30 (x-5)(x-6)=x²-11x+30

1)乘积式中的一次项系数、常数项与两因式中的常数项有何关系?一次项系数=两因式的常数项的代数和常数项=两因式的常数项的乘积(2)把以上各式呈现的规律,用公式表示出来.(x+a)(x+b)=x^2+(a

用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.

#includesintjiesheng(intn)//用于计算阶乘如:3!{if(n=1)rerunn;returnn*hh(n-1)}doubledigui(intn,intx)//用以计算y=x

if(counter==0&&Re_buf[0]!=0x55) return;是什么意思?

就是说counter的值为0的时候而且Re_buf[0]的值不是Ox55,整个函数结束.如果是在main函数中,可以理解为整个程序结束

用简便方法计算5.5X13.6-0.36X55 脱式计算!

5.5X13.6-0.36X55=5.5X13.6-5.5X3.6=5.5X(13.6-3.6)=5.5X10=55

5x方-11x-21=o x=?

5x²-11x-21=05x²-11x=215[x²-11x/5+(11/10)²]=21+5×(11/10)²(x-11/10)²=541