(1-x分之2)除以x方-4分之x方-4x-4-x 2分之x 4-搜答案-拍题作业网

x减2y分之x减y除以x方减4xy加4y方分之x方减y方=[(x-y)/(x-2y)]×[(x-2y)²/(x+y)(x-y)]=(x-2y)/(x+y)=[(1+√2-2(1-√2)]/(

解答如下图所示：

((x+2)/(x^2-2x)-(x-1)/(x^2-4x+4))/((x^2-16)/(x^2+4x))=((x+2)(x-2)-(x-1)x)/((x-2)^2*x)/((x-4)/x)=((x-

看你的题目都看了很少时间(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1)=(x-4)/(x^2-1)[(x^2+2x+1)/(x^2-3x-4)]+1/(x-1)

没有问题请采纳,有问题欢迎再追问!

5x³-6x²+15x-28____________________x+2)5x⁴+4x³+3x²+2x+15x⁴+10x³_

-2^3*4/9/(-3/2)^2-(-1/9)^2=-8/27*(-4/9)-1/81=32/243-1/81=29/243

自己想

原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x+3)(x+5)]\(x^2+7x+13)=[(1分之x+2)-(1分之x+3)+(1分之x+

我操,你这样鬼能看懂啊?分子是啥分母是啥,那些加、除都在什么位置上啊?

化简结果：-X的3次方分之一乘以（5X方-4分之1乘以X+2分之1）

=[(4x+5)/(x+1)(x-1)-3(x+1)/(x+1)(x-1)]÷(x+2)/(x+1)(x-1)=[(4x+5)-3(x+1)]/(x+1)(x-1)×(x+1)(x-1)/(x+2)=

1x-2x(x-2)=---+--------÷--------x(3x-1)^23x-111=---+------÷xx3x-13x-11=--------+-------x(3x-1)x(3x-1

把每个式子因式分解x的方+5x+4=（x+1）(x+4)x方-5x+6=(x-2)(x-3)………………

(x+y)/(x^4-y^4)÷1/(x^2+y^2)=(x+y)/(x^2+y^2)(x^2-y^2)÷1/(x^2+y^2)=(x+y)/(x^2-y^2)=(x+y)/(x+y)(x-y)=1/

=(x-4)/(x+1)(x-1)除以(x-4)(x+1)/(x+1)平方+1/(x-1)=(x-4)/(x+1)(x-1)乘以(x+1)平方/(x-4)(x+1)+1/(x-1)=(x-4)/(x+

原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]×x/(x-4)=[(x²-4-x²+x)/x(x-2)²]×x/(x-4)=[(x-4)/x(x-

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