17(x^2 y^2)-16*abs(x)*y=225-搜答案-拍题作业网

"3y/x+y"+"y/y-x"+"2x/x^2-y^2"=[3y*(x-y)-y(x+y)]/[(x+y)(x-Y)]=(2xy-4y^2)/[(x-y)(x+y)]=2xy/(x+y)a+2/a^

B={(x,y)|(a^2-4)x+(a-2)y=16}当a=2,B为空集,符合题意当≠2时,)A集合中的元素是直线L1:(y-2)/(x-1)=a+2是的点除去点(1,2)B集合中的元素为直线L2:

a(y-x)-2b(x-y)=a(y-x)+2b(y-x)=(y-x)(a+2b)

(2x+y)(2x-3y)+x(2y+y)=(2y+y)(2x-3y+x)=(2y+y)(3x-3y)=3(2y+y)(x-y)2a(x-y)-4b(x-y)=2(x-y)(a-2b)

8a(x-y)2_4b(y-x)

解题思路：提取公因式4(x-y)进行分解，注意把因式化简解题过程：解：

（1）3a³+6a²+3a=3a（a²+2a+1）=3a（a+1）²（2）原式=x²（x-y）-9（x-y）=（x-y）（x²-9）=（x-

3a(x-y)-2(y-x)^2=3a(x-y)-2(x-y)^2=(x-y)[3a-2(x-y)]=(x-y)(3a-2x+2y)

(4x-3y)²-16y²=(4x-3y+4y)(4x-3y-4y)=(4x+y)(4x-7y)x²+2x(y-z)+(z-y)²=x²+2x(y-z

1.(a²+a+1)(a²-a+1)=[(a²+1)+a][(a²+1)-a]=(a²+1)²-a²=a^4+2a²+1

∵(y-3)/(x-1)=2,x≠1,可化为y-2x=1,∵A∩B=空集,∴y-2x=1方程组无解ay+4x=16∴1/a=-2/4≠1/16解得a=-2又x≠1,则y≠3,∴3a+4≠16,a≠4当

(x+y)^2-16(x-y)^2

第一种：用平方差公式,原式=(x+y)^2-(4(x-y))^2=(x+y-4(x-y))(x+y+4(x-y))=(5y-3x)(5x-3y)第二种：全展开合并同类项,原式=x^2+y^2+2xy-

19（a-b)^2-16(a+b)^2=-7a^2-50ab-7b^2=-(7a+b)(a+7b)23x^3-12x^2y+12xy^2=3x(x^2-4xy+4y^2)=3x(x-2y)^2325(

设A={(x,y)}|3x+2y|.

3x+2y=1x-y=2解联立方程得x=1,y=-1A∩B={(x,y)|x=1,y=-1}B和C所代表的两直线平行,无交点(即空集)所以B∩C={Φ}A和D所代表的两直线重合,所以A∩D=A={(x

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1、=a²(x-y)-16(x-y)=(x-y)(a²-16)=(x-y)(a+4)(a-4)2由(2)得x=2+y/2(3)把(3)代入(1)得4+y+y=3∴y=-1/2把y=

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-5a^2+25a;=-5a(a-5)25x^2-16y^2=(5x-4y)(5x+4y);x^3-25x;=x(x-5)(x+5)x^2(x-y)+y^2(y-x);=x²(x-y)-y&

(x+y)(a-2b)

原式=x(a-2b)+y(a-2b)=ax-2bx+ay-2by

原式=(x-y)²[a²-2a(x-y)+(x-y)²]=(x-y)²[a-(x-y)]²=(x-y)²(2a-x+y)²