α1=(6,4,1,9,2)求向量组的秩-搜答案-拍题作业网

sina=±根15/4,tana=根15

=(1+1000)*1000/2=1001*500=500500

再答：给个好评呗^O^

PrivateSubCommand1_Click()GetNextNumber"",0,4,10EndSubPrivateSubGetNextNumber(ByVal已取得串AsString,Mini

小学就有月考了,真是丧心病狂.能上个清楚点的图么,眼太累了再问：哇谢谢再问：再问：这是最后一张卷子了，实在不想做了，天天做5张语文数学各5张。谢谢你帮我解答再问：再答：五年级就

fx=4cosxsin(x+π/6)-1=4cosx[sinx(√3/2)+(1/2)cosx]-1=2√3sinxcosx+2cos²x-1=√3sin2x+cos2x=2sin(2x+π

4的a次幕=1/2即2的2a次方=2的-1次方2a=-1a=-1/2

75度

y-π/4=ractan(2x-1)tan(y-π/4)=2x-1x=1/2[tan(y-π/4)+1]=1/2tan(y-π/4)+1/2∴反函数y=1/2tan(x-π/4)+1/2再问：不该考虑

答案1:[(4+5+9)+(8-7)+3-(2-1)]X6=126答案24-1)X(6-5)X(9-8)X7X3X2=126答案39-8)X(5-4)X(2-1)X7X6X3=126答案44-1)X(

因为y=1/2x^2-4x+3=1/2(x^2-8x+6)=1/2(x^2-8x+16-10)=1/2(x-4)^2-5所以y≥-5(即值域)

1.设t=2^x由于：4*4^x-5*2^x-6=0则：4*(2^x)^2-5*2^x-6=0即：4t^2-5t-6=0则有：(t-2)(4t+3)=0由于：t=2^x>0恒成立故：4t+3>0则：t

9^n=2,3^(2n)=2,因为3^m=6,所以3^m/3^(2n)=3^(m-2n)=6/2=3所以m-2n=12^(2m-4n+1)=2^[2(m-2n)+1]=2^[2+1]=2^3=8还是[

∵y=9x^2-6x+6=9[x-(1/3)]^2+5∴当x=1/3时,y有最小值且ymin=5.∵y=-4x^2+28x+1=-4[x-(7/2)]^2+50∴当x=7/2时,y有最大值且ymax=

A=[203;412;936]A=203412936>>rank(A)ans=3

原式=1-4(x-2y)把x-2y=5带入原式得：原式=1-4*5=-19

1-2正确3.D4.D5.C

1/7[-1/5(x+2/3+12/3)-6]+8=91/7[-1/5(x+14/3)-6]+8=91/7[-1/5x-14/15-6]+8=9-1/35x-2/15-6/7+8=9-1/35x-14

1,2,6,9求24点

(2*9+6)*1(9-1)×(6÷2)9÷1×2+69÷(1÷2)+66+2÷1×9