[1-x 2分之1]÷x²-4分之x² 2x 1
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第一天题答案是x+3分之x-2
你可以把这式子化简了挺简单的化简完就发现X都约掉啦式子是个定值所以X怎么变值都不变看错也没事什么公式?这题就得动笔算啊
(x²+2x+1)/(x²-y²)÷(x+1)/(x-y)=(x+1)²/(x+y)(x-y)×(x-y)/(x+1)=(x+1)/(x+y)【俊狼猎英】团队为
已知:(x²+1)/x=x²/x+1/x=x+1/x所以:x²+1/x²=x²+1/x²+2-2=(x+1/x)²-2
x=7(x²-x+1)7x²-7x+7=x7x²+7=8x两边平方49x4+98x²+49=64x²两边减去49x²49x4+49x&sup
x+1/x=3,两边同时平方得到x^2+1/x^2+2=9所以x^2+1/x^2=7x^2/(x^4+x^2+1)=1/(x^2+1/x^2+1)=1/(7+1)=1/8
X1+X2=-B/A=2X1*X2=C/A=1/2求得X1=1+根号2或者X1=1-根号2从而求出X2的值X1/X2+X2/X1=(X1*X1+X2*X2)/(X1X2)=6
方程两边同时乘以x(x+1)(x-1)得:5(x-1)+3(x+1)=7x解得:x=2检验:x(x+1)(x-1)=6所以x=2是原分式方程的解
=2x/(x+2)(x-2)-(x+2)/(x+2)(x-2)=[2x-(x+2)]/(x+2)(x-2)=(2-x)/(x+2)(x-2)=-1/(x+2)
原式=(x+1)/(x-1)-x(x-2)/(x+1)(x-1)÷(x-2)(x+1)/(x+1)²=(x+1)/(x-1)-x/(x-1)=(x+1-x)/(x-1)=1/(x-1)请好评
x+2分之x-2+x2-4分之4=1(x-2)/(x+2)+4/(x²-4)=1[(x-2)²+4]/(x²-4)=1[(x-2)²+4]=(x²-4
x+1/x=10x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/[(x+1/x)^2-1]=1/(10^2-1)=1/99
其实第n项=n*(n+1)=n^+n;则前n项的和为n(n+1)(2n+1)/6+n(n+1)/2=n(n+1)(n+2)/3.题目:带入即可得2010/3
x的2次方-2x分之x+2再-去x2次方-4x+4分之x-1=x(x-2)分之x+2-(x-2)²分之x-1=x(x-2)²分之(x+2)(x-2)-x(x-2)²分之x
x²+2x+1=10(x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【(x²+4)/x-4】÷【(x²-4)/(x²+2x)】=【(x&
{1-x/(x-1)}÷1/x(x-1)=(x-1-x)/(x-1)÷1/x(x-1)=-1/(x-1)÷1/x(x-1)=-x
发照片呀再问:请原谅手机不行再问:请帮我一下,谢谢。再答:看不明白再问:你写出来就行了的再答: 再答:是这样吗再问:嗯,麻烦把过程写详细点再答:我说题目对不再问:是的再问:对的再问:还有一个
因为x又x分之1=3,即x+1/x=3所以x+1/x=7则x^4+1/x^4=47所以:(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)=
x1+x2=4x1x2=-1(x1+x2)^2/(1/x1+1/x2)=(x1+x2)^2*x1x2/(x1+x2)=x1x2*(x1+x2)=-4
原式=2x/[(x-2)(x+1)]*(x+1)/(x-1)-x(x+2)/[(x+2)(x-2)]=2x/[(x-2)(x-1)]-x/(x-2)=[2x-x(x-1)]/[(x-2)(x-1)]=