y分之x=2 xy分之x-x加y分之y

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X分之1加Y分之1=2,则2X减XY加2Y除以3X加5XY加3Y=?

1/x+1/y=2(x+y)/xy=2x+y=2xy(2x-xy+2y)/(3x+5xy+3y)=[2(x+y)-xy]/[3(x+y)+5xy]=(4xy-xy)/(6xy+5xy)=3xy/11x

若xy分之y减x等于3,求分x减2xy减y分之2x加3xy减2y

(y-x)/xy=3求(2x+3xy-2y)/(x-2xy-y)?(y-x)/xy=3-->1/x-1/y=3-->y-x=3xy(2x+3xy-2y)/(x-2xy-y)=(x-y)/(-5xy)=

已知:x分之1加y分之1等于3,求x+2xy+y分之2x+3xy+2y的值

分子分母同除以xy,分子变为2(1/x+1/y)+3=2x3+3=9分母变为(1/x+1/y)+2=3+2=5答案是9/5

已知xy分之x加y等于2,求3x减5xy加3y分之负x加3xy减y.急 快...

xy分之x加y等于2∴x+y=2xy3x减5xy加3y分之负x加3xy减y=[-(x+y)+3xy]/[3(x+y)-5xy]=(-2xy+3xy)/(6xy-5xy)=xy/(xy)=1

已知x分之一加y分之一等于3求2x+xy+2y分之x-2xy+y

答:1/x+1/y=3(x-2xy+y)/(2x+xy+2y)分子分母同除以xy得:=(1/y-2+1/x)/(2/y+1+2/x)=(3-2)/(3*2+1)=1/7

已知x+y=-3,xy=2,求根号y分之x加根号x分之y的值

x+y=-3x=-y-3xy=2(-y-3)y=2-y²-3y-2=0y²+3y+2=0(y+1)(y+2)=0y1=-1y2=-2一、当y1=-1时,x1=-2,根号y分之x加根

已知x,y 满足x的平方加y的平方加4分之5等于2 x加y,求x加y分之xy

x方+y方+5/4=2x+y(x方-2x+1)+(y方-y+1/4)=0(x-1)方+(y-1/2)方=0x=1,y=1/2xy/(x+y)=1/3

若x分之1减y分之1等于2,则y减xy减x分之3x加xy减3y的值等于多少

x分之1减y分之1等于2(y-x)xy=2y-x=2xyy减xy减x分之3x加xy减3y=[3(x-y)+xy]/(y-x-xy)=(-6xy+xy)/(2xy-xy)=-5xy/xy=-5

已知x分之1加y分之1等于3,求x减2xy加y分之3x加xy加3y的值

此题简单做法你直接可以设X=1,Y=0.5,使其满足前面的条件即可,带入后面分式,后面的式子中文表述不清,

2x+2y分之3y 加 x²+xy分之2xy

3y/(2x+2y)+2xy/(x²+xy)=3y/(2x+2y)+2y/(x+y)=3y/(2x+2y)+4xy/(2x+2y)=7y/(2x+2y)

(x+y分之x加x+y分之2y)乘x+2y分之xy除(x分之1加y分之1)等于?

原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/

y分之x等于2分之1求x平方减xy加y平方分之x平方加2xy加y平方的值

3∵x/y=1/2∴y=2x故(x^2+2xy+y^2)/(x^2-xy+y^2)=(x+y)^2/(x^2-xy+y^2)=(x+2x)^2/(x^2-x·2x+4x^2)=9x^2/(3x^2)=

x的平方+xy分之x+3y加xy+y的平方分之y-x分式

(x+3y)/(x²+xy)+(y-x)/(xy+y²)=(x+3y)[x(x+y)]-(x-y)/[y(x+y)]=[(x+3y)y-x(x-y)]/[xy(x+y)]=(xy+

已知x分之1,加y分之1等于-3,求3X+2XY+3Y分之X-6XY+Y的值,知道的求解,

因为1/x+1/y=-3所以(x+y)/xy=-3即x+y=-3xy所以(x-6xy+y)/(3x+2xy+3y)=(-3xy-6xy)/[3(x+y)+2xy)]=-9xy/(-9xy+2xy)=9

已知x加y分之xy等于2,求负x加3xy减y分之3x减5xy加3y

已知xy/(x+y)=2,求:(3x-5xy+3y)/(-x+3xy-y)xy/(x+y)=2得:xy=2(x+y)(3x-5xy+3y)/(-x+3xy-y)=(3x-9xy+3y+4xy)/(-x

已知xy分之【x加y】等于2分之一,则【xy加x加y】分之xy等于多少

xy分之【x加y】等于2分之一xy=2(x+y)【xy加x加y】分之xy=2(x+y)/[2(x+y)+x+y]=2(x+y)/[3(x+y)]=2/3

根号x减根号y分之(x减y)加(根号x加根号y)分之x加y加2根号xy

=2倍(x-y)分之(x根号x-y根号y)+2根号xy.=(x-y)分之[2x根号x(1+根号y)-2y根号y(1+根号x)].