y=in^2(1-x)的微分
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 10:09:23
y=x/(1-x^2)y'=[(x)'(1-x^2)-x*(1-x^2)']/(1-x^2)^2=[(1-x^2)-x*(-2x)]/(1-x^2)^2=(1+x^2)/(1-x^2)^2故dy=y'
第一题,这是个隐函数,两边对x求导得:2y'-1=(1-y')*ln(x-y)+(x-y)*(1-y')/(x-y)=(1-y')*ln(x-y)+(1-y')所以[3+ln(x-y)]y'=ln(x
[In(3x+1)]'=1/(1+3x)*(3x)‘=3/(1+3x)dy=y'dx=3dx/(1+3x)
两边对x求导:2-y'=(y'-1)ln(y-x)+(y-x)*1/(y-x)*(y'-1)=(y'-1)[ln(y-x)+1]2-y'=y'[ln(y-x)+1]-[ln(y-x)+1]y'[ln(
dy/dx==-(2e^x)/x^3+(e^x)/x^2我用数学软件算的,绝对不会错.
如果对x求导,则ln|x|=yln|y|,1/x=y'/y+yy'/y=y'/y+y',.对数求导法.如果对y求导,则ln|x|=yln|y|,x'/x=ln|y|+y/y,x'=y^y(1+ln|y
分步积分.先把e^-2x放进去.再问:可以写具体过程吗?再答:看我插入的图片。
1y`=1+2xdy=(1+2x)dx2y`=2tanx(secx)^2dy=[2tanx(secx)^2]dx
两边即对数得:lnz=xy*ln(lnu),不妨记u=x^2+y^2z'x/z=yln(lnu)+2x^2y/lnu,z'x=z[yln(lnu)+2x^2y/lnu]z'y/z=xln(lnu)+2
1.d(cosx)^2=2cosx(-sinx)dx=-sin2xdx2.dsin(x²-1)=cos(x²-1)d(x²-1)=cos(x²-1)×2xdx=
y=arcsin√(1-x^2)y'=-x/(|x|√(1-x^2))∴dy=-xdx/(|x|√(1-x^2))当x>0dy=-dx/√(1-x^2)当x
y'=2^(x²)*ln2*(x²)'=2x*2^(x²)*ln2
∵y=x/(x^2+1)^(1/2)∴dy=d[x/(x^2+1)^(1/2)]=[x/(x^2+1)^(1/2)]′dx={[(x^2+1)^(1/2)-x^2/(x^2+1)^(1/2)]/(x^
1)dy=d(e^(-2x)*cos3x)=[-3sin3xe^(-2x)-2cos3xe^(-2x)]dx2)dy=d((x^2+1)/(x+1))=[2x(x+1)-(x^2+1)]/(x+1)^
y=[ln(1-x)^2]^2y'=2[ln(1-x)^2]*[ln(1-x)^2]'=2[ln(1-x)^2]*[2ln(1-x)]'=2[ln(1-x)^2]*2*1/(1-x)=4*[ln(1-
y'=2e^2xcos(e^2x)把y看成复合函数sint,t=e^m,m=2x.复合函数求导,等于三个分别求导的积
dy=d(1/x²)+d(lnx)=(-2/x³)dx+(1/x)dx=[(x²-2)/x³]dx
-sinx-2x
dz=2xydx+x^2dy再问:有全过程吗再答:en我想知道这里的X^2Y是指的X得平方乘以Y吗?如果是过程如下:dz/dx=2xydz/dy=x^2dz=2xydx+x^2dy再问:是X的2Y次方