y=(1 5)^(2x-x²)的定义域与值域

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已知2/x+2/y=根号24,求 x/y(x-y) - y/x(x-y)的值

2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]

已知2/x 2/y=根号24,求 x/y(x-y) - y/x(x-y)的值

你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=(x平方-y平方)/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24

化简求值:[2x的平方-(x+y)(x-y)][(-x-y)(y-x)+2y的平方],其中x=1,y=2

[2x的平方-(x+y)(x-y)][(-x-y)(y-x)+2y的平方]=[2x²-(x²-y²)][(x+y)(x-y)+2y²]=(2x²-x&

先化简,再求值 [(x-y)的平方+(9x+y)(x-y)]÷2x,其中x=3,y=15

[(x-y)的平方+(9x+y)(x-y)]÷2x=(x-y)(x-y+9x+y)÷2x=5x-5y当x=3,y=15得原式=15-75=-60

已知x,y的值满足方程组x+2y=3,x-y=-2,求x/(x-y)²+x²-y²/(x+

x+2y=3(1)x-y=-2(2)消去y,(1)+(2)×2得:x+2x=3-43x=-1x=-1/3消去x,(1)-(2)得:2y+y=3+23y=5y=5/3方程组的解为x=-1/3,y=5/3

已知x+y/x=11/8,求x-y/x+2y的值

(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19

若(x-2)的平方+15y-11=0,求代数式-3(2x-y)-{7x-[6x+2y-(10x-8y

-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}=-6x+3y-7x+(6x+2y-10x+8y)+x+6x-8y=-13x+3y-4x+10y+7x-8y=-10x

已知2x-y/x+2y=3,求2(2x-y)/x+2y-9(x+2y)/2x-y+3的值.

∵2x-y/x+2y=3∴2(2x-y)/x+2y-9(x+2y)/2x-y+3=2×3-9×1/3+3=6

已知x-y/x=x/x-2y(y不等于0),求x:y的值

X/X···这是什么意思···再问:x减y分之x等于x分之x减2y再答:两边同乘x(x-2y)再问:再答:题目是什么····就给个图啊···再问:如图,已知EFGH为矩形,AD⊥Bc于D,交HG于K,

y(x+y)+(x+y)(x-y)-x的2次方,其中X=-2,y=2分之一.

y(x+y)+(x+y)(x-y)-x的2次方,其中X=-2,y=2分之一y(x+y)+(x+y)(x-y)-x的2次方=(x+y)(y+x-y)-x=x(x+y)-x=x(x+y-1)=-2*(-2

已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?

即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²

已知x-y/x=x/x-2y(y不等于0),求x:y的值

如果是(x-y)/x=x/x-2y,则x:y=2:3(x-y)/x=(x-2y+2y)/x-2y1-y/x=1+2y/(x-2y)-y/x=2y/(x-2y)x/y=(x-2y)/-2yx/y=-1/

化简:【(x-y)的2次方+(x+y)(x-y)】除以2x,其中x=3,y=1.5

原式=[(x-y)(x-y)+(x+y)(x-y)]/2x=(x-y)(x-y+x+y)/2x=(x-y)·2x/2x=x-y=3-1.5=1.5

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

5x=3y,(2x+y)的平方=5x(x+y)+9

5x=3y,x=3y/5(2x+y)的平方=5x(x+y)+94x²+4xy+y²=5x²+5xy+9x²+xy-y²+9=09y²/25+

已知x+y/y=11/8,求x-y/x+2y的值.

x+y/y=11/8说明11y=8(x+y)即8x=3y所以x-y/x+2y=3(x-y)/3(x+2y)=(3x-3y)/(3x+6y)=(3x-8x)/(3x+16x)=-5/19

1奥数题x-2y/x+2y=3,求x-2y/3(x+2y)-3(x-2y)/x-2y的差

(x-2y)/(x+2y)=3取倒数(x+2y)/(x-2y)=1/3所以原式=(1/3)[(x-2y)/(x+2y)]-3[(x+2y)/(x-2y)]=(1/3)×3-3×(1/3)=0