x^2-6x (a-2) | x-3| 9-2a=0

照相机

|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|

x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊

x*2x=4x4x*3x=11x11x*4x=26x26x*5x=57x57x*6x=120x120x*7x=247x247x*8x=502x502x*9x=1013x=3039x=3

2x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/7

题目是不是：a(x*x+x-c)+b(2x*x-x-2)=7x*x+4x+3?a(x*x+x-c)+b(2x*x-x-2)=7x*x+4x+3,即（a+2b)x^2+(a-b)x-(ac+2b)=7x

x²+x+a

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

原式=(x+2)/(x+2)(x-3)-2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)-2/(x-3)-(x+1)/(x-3)²=-1/(x-3)-(x+1)/(x-

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

由题意得当x*x+x-2=0时原多项式=0所以当x=1,-2时原多项式=2x*x*x*x-3x*x*x+ax*x+7x+b=0即2*1*1*1-3*1*1+a*1*1+7*1-b=0且2*(-2)*(

解1：原式=x(x-1)/(x+1)*(x+1)/x=x-1解2：原式=(x+3)^2/(x+3)(x-3)*(x-3)/(x+2)=(x+3)/(x-3)*(x-3)/(x+2)=(x+3)/(x+

(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-

x^2-6x+5=(x-5)(x-1)(x-2)(x-3)=x^2-5x+6,A错(x-6)(x+1)=x^2-5x-6,B错

3x/6x^2z=1/2xza+b/a^2-b^2=(a+b)/(a+b)(a-b)=1/(a-b)x^2+2x+1/x^2+x=(x+1)²/x(x+1)=(x+1)/x3x-6/x^2-

3x(x-5)≤(2x-9)(x-5)3x^2-15x≤2x^2-19x+45x^2+4x-45≤0(x+9)(x-5)≤0-9≤x≤5A={-9≤x≤5}2x^2-x-6>0(2x+3)(x-2)>

原式=[x/(x-3)]-[5x/(x²-x-6)]=[x/(x-3)]-(5x)/[(x-3)(x+2)]=[x(x+2)]/[(x-3)(x+2)]-(5x)/[(x-3)(x+2)]=

第一题：各式可变为：x²-3x+2=(x-1)(x-2),x²-18x+32=(x-2)(x-16),x²+x-6=(x-2)(x+3)所以选D第二题：(x+5)乘以(x

/>(1)3a(5a-2b)=15a^2-6ab(2)(x-3y)*(-6x)=-6x^2+18xy(3)x(x-1)+2x(x+1)-3x(2x-5)=x^2-x+2x^2+2x-6x^2+15x=

不知道你^这个符号什么意思暂且当成平方做吧x^2+4x+3=(x+1)(x+3)(2x-x)^2=x^2x^2+x=x(x+1)x^2+x-6=(x+3)(x-2)约分：得x/(x-2)再问：题目炒错