xy=ex y所确定的隐函数求导
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方程两边求关x的导数ddx(xy)=(y+xdydx); ddxex+y=ex+y(1+dydx);所以有 (y+xdy
这种题可以直接全微分,即e^xdx+xdy+ydx=0所以dy/dx=(e^x+y)/-x
隐函数求导,两边同时求导,此题是对X求导!两边同时求导:y+xy'=e^x-y'y'=(e^x-y)/(x+1)由XY=e^X-y解出yy=e^x/x+1,带入上式y'=(e^x-y)/(x+1)=[
方程两边对x求导:e^y×y'=y+xy'得y'=y/(e^y-x)
y^2-2xy+9=0两边分别对x求导数得:2y(dy/dx)-2y-2x(dy/dx)=0(dy/dx)(y-x)-y=0dy/dx=y/(y-x)
已知:x^(y²)+y²lnx=4即:e^[lnx^(y²)]+y²lnx=4即:e^[y²×lnx]+y²lnx=4两边求导得到:e^[(
∵dudx=∂f∂x+∂f∂y•dydx+∂f∂z•dzdx…(1)由exy-xy=2,两边对x求导得:exy(y+xdydx)-(y+xdydx)=0解得:dydx=-yx.又由ex=∫x-z0si
先移项:e=e^y+xy,再两边对x求导:0=e^y*y'+y+x*y',解得:dy/dx=y'=-y/(e^y+x)
y'=(y+xy')/(xy)xyy'-xy'=yy'=y/(xy-x)所以dy/dx=y'=y/(xy-x)
两边求导:e^(xy)*(xy)'-(xy)'=0e^(xy)*(y+xy')-(y+xy')=0ye^(xy)+xe^(xy)*y'=y+xy'x(e^(xy)-1)y'=y(1-e^(xy))y'
y+xy'+y'/y=0//对xy和lny分别求导,注意y是x的函数y'(x+1/y)=-y//移项,合并同类项y'=-y²/(xy+1)
xy+lny=1两边求导y+xy'+y'/y=0y'=-y/(x+1/y)=-y^2/(xy+1)
两边求导:y+xy'+y‘/y=0将x=0带入得到:y'=--y^2
两边分别求x的导数得:e^x+(y+xy')=0,即y'=-(e^x+y)/x,即:dy/dx=-(e^x+y)/x
y+x*y'=e^(x+y)*(1+y')∴dy/dx=[e^(x+y)-y]/[x-e^(x+y)].
cos(xy)=x-y,隐函数,两边求导-sin(xy)*(xy)'=1-y'-sin(xy)*(y+xy')=1-y'-ysin(xy)-xcos(xy)*y'=1-y'y'[1-xsin(xy)]
第一步方程两边对x求导记y+xy'-y'/y=2x第二步解出y'记y'=(2xy-y^2)/(xy-1)
e^xy(y+xy')=2+6yy'y'=(ye^xy-2)/(6y-xe^xy)dy=dx(ye^xy-2)/(6y-xe^xy)
e^(x+y)=xy两边对x求导:e^(x+y)*(1+y')=y+xy'解得:y'=[y-e^(x+y)]/(e^(x+y)-x]=(y-xy)/(xy-x)