作业帮﹣2x²y+12xy-16y因式分解
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 14:18:08
解法一用双十字相乘法分解x^2-2xy-8y^2-x-14y-6=(x^2-2xy-8y^2)-x-14y-6=(x-4y)(x+2y)-(x+14y)-6=[(x-4y)-3][(x+2y)+2]=
原式=x²-y²-(4x²y²+12xy²+9y²)=x²-y²-4x²y²-12xy²-
3xy是3x原式=(x-3y)(x+2y)+3x+y+2十字相乘x-3y2×x+2y1所以原式=(x-3y+2)(x+2y+1)
对.前提是x不等于y
(x+y-2xy)(x+y-2)+(1-xy)^2=(x+y)^2-2(1+xy)(x+y)+4xy+1-2xy+x^2y^2=(x+y)^2-2(1+xy)(x+y)+(1+xy)^2=(x+y)^
x^+2xy+y^+4=16(x+y)²=16-4=12(1)x^-2xy+y^=16(x-y)²=16(2)(1)-(2)2y*2x=-4xy=-1(3xy+6y^)+|x^-(
-12xy*3x^2y-x^2y*(-3xy)=-36x^3y^2+6x^3y^2=-30x^3y^2
=xy(x-y)×[-xy/(x-y)]=-(xy)²=-x²y²
【x²+xy/（x-y）】/【xy/（x-y）】=【x²（x-y）/（x-y）+xy/（x-y）】/【xy/（x-y）】={【x²（x-y）+xy】/（x-y）}/【xy
16x³-24x²y²+12xy^4-2y^6=(16x^3-16x^2y^2+4xy^4)-8x^2y^2+8xy^4-2y^6=4x(4x^2-4xy^2+y^4)-
（xy-y^2)÷x-y/xy=y(x-y)×[xy/(x-y)]=xy²
（4xy+12y)+[7x-(3xy+4y-x)]=4xy+12y+7x-3xy-4y+x=xy+8x+8y=xy+8(x+y)=(-2)+8*3=-2+24=22
(x+y)(x-y)-x(y+1)-y(y+1)=(x+y)(x-y)-(x+y)(y+1)=(x+y)(x-2y-1)
xy+y平方+x-y-2=xy+x+y^2-y-2=x(y+1)+(y+1)(y-2)=(y+1)(x+y-2)
(x+y)^2=16（x-y)^2=12相减得4xy=4xy=1
4x^2y+12xy+9y=y(4x^2+12x+9)=y(2x+3)^2
x^2y+4xy+4y=y(x²+4x+4)=y(x+2)²
原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&
解(x-y)/(xy-y²)=(x-y)/y(x-y)=1/y
利用公式法逆向因式分解(x+y)(x^2-xy+y^2)=x^3+y^3(x-y)(x^2+xy+y^3)=x^3-y^3都是公式可以自己乘开来试下可以抵消的（x^2-xy+y^2)和（x^2+xy+