sin2x (1 sin^2x)的不定积分

y=(sin2x)^2+sin2x=(sin2x+1/2)^2-1/4当sin2x=-1/2时,y取得最小值-/14；当sin2x=1时,y取得最大值2.所以,y的值域是[-1/4,2].再问：为什么

sin2x=-24/25cosx-sinx=7/5sin2x+2sin²x/1-tanx=-96/175sin2x=2sinxcosx=(sinx+cosx)²-sin²

y=1/2sin2x+sin^2x=1/2sin2x+(1-cos2x)/2=1/2sin2x-1/2cos2x+1/2=√2/2(sin2xcosπ/4-cos2xsinπ/4)=√2/2sin(2

y=1/2sin2x+1/2(1-cos2x)=1/2(sin2x-cos2x+1)=1/2[√2sin(2x-45º)+1]值域[1/2(1-√2),1/2(1+√2)]

∵y=[1+(sinx)^2]/sin2x=[1+(1-cos2x)/2]/sin2x=(3-cos2x)/(2sin2x)=3(csc2x)/2-(cot2x)/2∴y'=[-2*3(csc2x)(

/>Y=1/2sin2x+sin^2x=1/2sin2x+(1-cos2x)/2=1/2+√2/2(√2/2*sin2x-√2/2*cosx)=1/2+√2/2sin(2x-π/4),因为sin(2x

再问：分母是sin2x不是2x再答：x趋向0时sin2x～2x再问：哦哦哦对哦!!谢谢

sin^2(x)+cos^2(X)=1,原式=(3sin^2(x)+cos^2(x))/2sinxcosx,分式上下同除以cos^2(x),得原式=（3tan^2(x)+1)/2tanx,再将分子和分

y=1/2sin2x+(1-cos2x)/2=1/2(sin2x-cos2x)+1/2=√2/2*(√2/2*sin2x+√2/2zos2x)+1/2=√2/2*(sin2xzosπ/4+cos2xs

函数fx=2sin²x+sin2x－1=sin2x-cos2x=√2sin(2x-π/4)最大值=√2再问：�����ֵʱx��ȡֵ��ô��

求导数,导数为零时取最值再问：���԰���д�¹��ô��лл��再答：再答：����������һ�ַ���

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f(x)=(1-cos2x)/4+(1+cos2x)/2+√3sin2x/4=(1-cos2x+2+2cos2x)/4+√3sin2x/4=(cos2x+3)/4+√3sin2x/4=(cos2x+s

f(x)=sin^2x/2+cos^2x+√3/4sin2x=1/2+cos^2x/2+√3/4sin2x=1/2+(cos2x+1)/4+√3/4sin2x=1/2+1/4*cos2x+1/4+√3

学过导数求极值吗?或许能用,我忘了.

y=(2sin²x+1)/(sin2x)=（2sin²x+sin²x+cos²x)/(2sinxcosx)=3sinx/(2cosx)+cosx/(2sinx)

原式=(2sinxcosx-2sin²x)/(1-sina/cosx)=2sinx(cosx-sinx)/[(cosx-sinx)/cosx)]=2sinxcosx=sin2x=-cos(π

1=sin^2x+cos^2xy=(2sin^2x+sin^2x+cos^2x)/(2sinxcosx)=(3sin^2x+cos^2x)/(2sinxcosx)y=3/2*tanx+1/2*cotx

(sin2x-2sin^2x)/(1-tanx)=[2sinx*(cosx-sinx)]/[1-sinx/cosx]=[2sinx*(cosx-sinx)]/[(cosx-sinx)/cosx]=2s

f(x)=(1+cos2x+8sin^2x)/sin2xf(x)=(1+2cosx²-1+8sin²x)/2sinxcosxf(x)=(cosx²+4sin²x