输入若干个整数,以0结束,输出所有数的平方和

运行通过,有问题HI：#includeintmain(){intnum,n=0,m=0;do{scanf("%d",&num);if(num>0)m++;elseif(num

intmax;//接收最大值intarr[n];//n为输入的整数的个数inti;max=arr[0];for(i=0;imax)max=arr[i];//求最大值}这是核心语句,我希望你可以自己加上

/>1#include#includeintmain(){intx=0;while(1){printf("请输入x值:");scanf("%d",&x);if(x==0){break;}printf(

是输入结束不会还是取整数小数不会?再问：都不会，完全没有思路，只有寻求帮助了再答：������֪��˼·����ֱ��Ҫ����再问：ֱ��Ҫ����ϣ������C++��д��˳��˵������

顶一楼.如果楼主不想把-32767这个数计算在内的话,就把printf("正整数个数:%d\n负整数个数:%d\n0的个数:%d\n",a,c,b);改为printf("正整数个数:%d\n负整数个数

1.a2、n++

#include<stdio.h>void main(){    int sum=0;   &nb

#includeintmain(void){intmax=0;while(1){intnum=0;scanf("%d",&num);if(num==0)break;max=num>maxnum:max

#includeusingnamespacestd;intmain(){inta,b；floatc;//平均数应为浮点型,因为结果不一定是整数intn;coutn;if(n==0)break;//判断

#includeintmain(){intx,y;while(scanf("%d%d",&x,&y)==2&&(x!=0||y!=0)){\x09printf("%d\n",x+y);}return0

PrivateSubForm_Click()DimsAsInteger,maxAsInteger,minAsInteger,nAsInteger,averageAsSingle,sumAsLongDo

#includeintmain(void){intcount=0,n,sum=0;whlie(scanf("%d",&n)!=EOF){if(n==-1)break;elsesum+=n;count+

importjava.util.Scanner;publicclassMain{publicstaticvoidmain(Stringargs[]){Scannerinput=newScanner(S

用C语言吗再问：是的再答：#includeintmain(){inta=0,sum[4]={0,0,0,0};do{scanf("%d",&a);if(a==1)sum[0]++;if(a==2)su

.你把做为结束符的0也算进去了吧.在循环里判定一下,如果是0不做MIN==NUMif（NUM!=0）MIN=MIN

#include#includeintmain(){inta,sum=0;do{scanf("%d",&a);if((a/100)%10==3)sum+=a;}while(a!=0);printf("

#includevoidmain(){intmax(intx,inty;inta,b,c;scanf("%d,%d",&a,&b);c=max(a,b);printf("Thelargestnumbe

/*C语言程序设计题,要求输入若干个整数,以输入的是0结束,输出所有正整数的和以及所有数中的最大值,最好用for循环或者dowhile循环*///do.while语句#include"stdio.h"

#includevoidmain(){intmax,min,absmax;longtotal;intn,x;n=0;max=-32768;min=32767;absmax=0;total=0;whil

C语言编程如下：#includemain(){intnum=0,sum=0,a;while(a!=-32767){scanf("%d",&a);if(a>0){num++;sum+=a;}}print