输入整数,若为偶数则输出0,若为奇数则输出1

//仅供参考#includeintmain(){intn,sum=0;while(scanf("%d",&n)==1&&n+1){if(n%2==0)printf("%d\n",n);elsesum+

publicclassClient{publicstaticvoidmain(String[]args){factors(120);factors(1200);factors(349);factors

#includevoidmain(){inta;printf("Pleaseinputanumber:");scanf("%d",&a);if(a==0)printf("%disaevennumber

你看if下面那句y=0;根据题目的意思是：当x不为偶数即为奇数时才输出0.所以if里面的表达式是判断x是奇数.所以x%2!=0.如果x是偶数的话它除以2的余数是0.是奇数的话除以2的余数不可能是0.你

好像ACM的题哦.#includevoidmian(){intn;scanf("%d",&n);if(n%2==0){printf("%diseven",n);}else{printf("%disod

C语言的如下#includemain(){intx;printf("输入一个整数:");scanf("%d",&x);if(x==0)printf("zero\n");elseif(x%2==0)pr

#includeintmain(){inty=0,i,x;printf("inputx:");scanf("%d",&x);for(i=1;i

#includeintmain(){intx,y;while(scanf("%d%d",&x,&y)==2&&(x!=0||y!=0)){\x09printf("%d\n",x+y);}return0

输出x|——————————平方|||否乘以二|则||减去四————结果大于0|输出y这个的话答案是4.输入x——————↓————→（x为正数）y=x-5——输出y（x为负数）y=x的2次方+1——

已经调试,请采纳,如需注释,请追问另,负数都返回0,如需返回负数整数个数,使用fabs,或将字符串指针挪到符号之后.#include <stdio.h>#include 

#includeintjudge(intnum){returnnum%2==0?0:1;}main(){intn;while(scanf("%d",&n)!=EOF){if(judge(n))prin

#include<stdio.h>#include<string.h>#include "math.h"void fun(){\x09p

inputaifmod(a/2)=0?a/2+3endif

#includeintmain(void){inti;scanf("%d",&i);if(i%2==0)printf("it'saEven");/*输出偶数*/elseprintf("it'saodd

publicstaticvoidmain(String[]args){intarray[]=newint[20];intresult=0;Listlist=newArrayList();System.

#includeusingnamespacestd;intmain(){inta,b;cin>>a>>b;if(a%b==0&&a>b){cout

inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=

=a%2,若b值为1,输出no,否则yes再问：请输入pascal程序再答：抱歉，不会

defodd_even(nums):odd=0even=0foriinnums:ifi%2==0:even=even+ielse:odd=odd+iprint"oddsum

#includemain(){intnum,yushu;printf("Pleaseenterthenumber\n");scanf("%d",&num);yushu=num%2;if(yushu==