输入两个整数及运算符,要求输出运算结果的程序怎么写?

#includevoidmach(intx,inty){printf("x²+y²=%d\n",(x*x+y*y));printf("x²-y²=%d\n",(

#includevoidmain(){chara;intix,iy;printf("请输入式子:");scanf("%d%c%d",&ix,&a,&iy);if(a=='+')printf("ix+i

#includeintmain(){inta,b;scanf("%d%d",&a,&b);printf("%d",a-b);return0;}

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S

Reverse

#includeintmain(){intm,n;do{printf("输入两个非零整数:\n");scanf("%d%d",&m,&n);}while(m==0||n==0);printf("%d+

maylab软件挺好编写的用c语言也不难

#includevoidmain(){inta1,a2;floate;scanf("%d%d",&a1,&a2);printf("%d+%d=%d\n",a1,a2,a1+a2);printf("%d

求逻辑表达式还是画图?再问：逻辑表达式，不知道怎么抽象再问：麻烦你了再答：再答：列表：A1A0---------Y3Y2Y1Y0000011010100100111111100所以（反斜杠表示“非”）

#includeusingnamespacestd;intmain(){\x09inta=0,b=0,c=0;\x09coutb>>c;\x09if(a>b&b>c)\x09{\x09\x09cout

staticvoidMain(string[]args)　　{　　stringstr="",math="";　　while(true)　　{　　boolIsOk=true;　　Console.Writ

输入4,输出1234123412341234（样例）#includevoidmain(){intn;inti,j;scanf("%d",&n);for(i=1;i

#includevoidmain(){floata=0,b=0,c=0;chard;printf("输入两个数:\n");scanf("%f%f",&a,&b);getchar();printf("选

#includeusingnamespacestd;intmain(){inta,b;cout

#includevoidmain(){inta,b,c,min,max,cha;scanf("%d%d%d",&a,&b,&c);min=a;max=a;if(b>max){max=b;}if(bma

#includeintmain(){floata,b,s,m,n,j;scanf("%f",&a,b);s=a+b;m=a-b;n=a*b;j=a/b;printf("%f\n",s,m,n,j);r

#include"stdio.h"main(){inta,b;printf("请输入两个数")；scanf("%d",&a);scanf("%d",&b);printf("a=%d,b=%d,a+b=

#includeusingnamespacestd;intmain(){floata,b,c,d,e,f;cin>>a;cin>>b;if(a!=0&&b!=0){c=a+b;d=a-b;e=a*b;

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){intm,n,k,l;while(1){printf("Typem

#includeintmain(){inta,b,i,c,d,m,n;scanf("%d%d",&m,&n);for(i=m;i>=1;i--){a=m%i;b=n%i;if(a==0&&b==0){