输入两个整数,输出两者的和.差.商和商的余数

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

#includevoidmain(){floata,b,c,d,e;printf("请输入两个实数:");scanf("%f%f",&a,&b);c=a-b;d=a+b;e=a*b;printf("\

用什么语言编写再问：c语言

#includevoidmach(intx,inty){printf("x²+y²=%d\n",(x*x+y*y));printf("x²-y²=%d\n",(

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09printf("商为%.2f余数为%d\n",1.0*a/b,a%b);\x09ret

#include"stdio.h"main(){inta,b;printf("请输入两个整数(a,b)：");scanf("%d,%d",&a,&b);printf("和：%d\n",a+b);pri

除数为0时怎样做、不为0时怎样做,不用分支结构是处理不了这种问题的,亲.再问：大哥、、、、求解。。。我郁闷了。。。再答：汗，唯一的办法就是用分支结构，if(b=0){//输出错误信息printf("除

#includeintmain(){inti,j,sum1,sum2;inta[1000],n;sum1=sum2=0;//分别记录偶数和奇数的和scanf("%d",&n);//记录整数个数

#include#incluedvoidmain(){inta;intb;intc,d;a=1500,b=350;c=a/b;//商数d=a%b;//余数pritf("商数为:%d\n",c);pri

#includeintmain(){inta,b,c,d=0;scanf("%d%d",&a,&b);c=a/b;d=a%b;printf("商是:%d\n",c);printf("余数是:%d\n"

#includevoidmain(){inta1,a2;floate;scanf("%d%d",&a1,&a2);printf("%d+%d=%d\n",a1,a2,a1+a2);printf("%d

print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Ente

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

#include#includeintmain(){inta,sum1=0,sum2=0;printf("putdata");while(scanf("%d",&a)!=0){if(a%2==0)su

#include"stdio.h"intmain(intargc,_TCHAR*argv[]){inta=0;intb=0;printf("请输入数值");scanf("%d%d",&a,&b);pr

a=Int(InputBox("a="))b=Int(InputBox("b="))c=Round(Rnd()*(a-b)+b,0)MsgBox"a="&a&";b="&b&";c="&c

请问用什么语言编写?再问：我的失误！用C#

#includevoidmain(){inta,b,c,min,max,cha;scanf("%d%d%d",&a,&b,&c);min=a;max=a;if(b>max){max=b;}if(bma

程序如下：#includevoidmain(){\x05intnum1,num2,sum,min,mul,yushu;\x05floatshang;\x05scanf("%d",&num1);\x05

importjava.util.Scanner;publicclassTest20010{publicstaticvoidmain(Stringargs[]){\x05intnum1,num2;\x0