诺5x-6y＝0,且xy≠0,则5x-3y分之5x-3y的值等于多少?

5x-6y=05x=6y所以10x=12y所以原式=(12y-4y)/(12y-3y)=8y/9y=8/9

x+6y=5√xy(√x-2√y)(√x-3√y)=0√x=2√y√x=3√y所以x=4y或x=9y√x=2√y原式=(8y+2y-y)/(4y+2y+2y)=9/8√x=3√y原式=(18y+3y-

x+6y=5根号xyx+6y-5根号xy=0(√x-2√y)(√x-3√y)=0√x-2√y=0或√x-3√y=0（1）√x-2√y=0√x=2√yx=4yx+根号xy+2y分之2x+根号（xy-y）

x-5*根号xy-6y=0(根号x-6*根号y)(根号x+根号y)=0因为x和y都大于0,所以根号x-6*根号y=0根号x=6根号yx加根号xy减2y分之x减2根号xy加y分子：x减2根号xy加y=(

x-5xy+6y=0(√x-2√y)(√x-3√y)=0所以√x=2√y,√x=3√yx=4y或x=9y原式=(8y)/(9y)=8/9或=(14y)/(20y)=7/10

∵x-y=6,xy=4∴(x-y)²=36∴x²-2xy+y²=36∴x²+y²=36+2×4=44两边除以xyx/y+y/x=44/4=11∴xy^

是"已知y-2x=0,求代数式[（x²-y²）（x²-xy+y²）]÷[（x²+xy+y²）（x²+y²）]的值"这道题

由题设可知y=xy-1，∴x=yx3y=x4y-1，∴4y-1=1，故y=12，∴12x=x，解得x=4，于是x+y=4+12=92．故答案为：92．

再问：帅再问：谢了再答：过奖了

是不是x-5√xy-6y=0?(√x-6√y)(√x+√y)=0x>0,y>0则√x+√y>0所以√x-6√y=0√x=6√yx=36y所以√xy=6y所以原式=(36y-12y+y)/(36y+6y

x^2-xy-2y^2=0(x-2y)(x+y)=0x=2y或x=-y(x^2-2xy-5y^2)/(x^2+2xy+5y^2)=(x^2-xy-2y^2-xy-3y^2)/(x^2-xy-2y^2+

-2x+6xy-2y/(7x+5y)-9xy-(3x+y)=[3(x+y)-x-y]/[7x+5y-9/2(x+y)-3x-y]=2(x+y)/[-1/2(x+y)]=-4

(x+y)(x²-xy-y²)=0,=>x^3-y^3=0,x=y（x²-2xy-5y²）/（x²+2xy+5y²)=-6/8=-3/4=-

再问：太草率了吧。。直接写报纸上⊙▽⊙再答：不好意思，好久没学习了再问：。。。再答：等回头我买个本子去…再问：。。再问：不至于吧。。再答：哈哈

首先：十字相乘因式分解将x+5根号xy-6y=0分解为（根号x+6根号y）（根号x-根号y）=0所以x=y,另一个由于x＞0,y＞0舍去这样化简后面的式子就

x²-4xy+4y²=0(x-2y)²=0则x=2y,因为xy≠0,则x≠0且y≠=0那么(x-y)/(x+y)=(2y-y)/(2y+y)=y/(3y)=1/3

因为,x-y=3xy所以：-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-

2X^2+3xy-2y^2=0(2x-y)(x+2y)=0即：2x-y=0或,x+2y=0y=2x或x=-2y当y=2x时：x+y/x-y=3x/(-x)=-3当x=-2y时：x+y/x-y=-y/(

∵x-y=4xy∴原式=[2(x-y)+3xy]/[-(x-y)-2xy]=(8xy+3xy)/(-4xy-2xy)=11xy/(-6xy)=-11/6

x^2+xy-6y^2=0化简得（x-2y)(x+3y)=0x=2y或x=-3y分别带入2x^2-3xy+y^2/5x^2-7xy+2y^2化简即可.