设计一个circle类计算圆的面积

OptionExplicitPrivateSubCommand1_Click()Label1.Visible=TrueDimrAs__single___Dim____s___AsDouble_cons

好难!

classcircle{intx;inty;floatradius;public:voidsetpoint(int&x,;int&y);voidsetradius(float&radius);floa

namespaceEX1_4{publicclassshape{publicdoublePI=3.14;}publicclassRectangle:shape{publicintx,y,s,l;pub

classCircle{public:Circle(intnr){r=nr;}Circle(){}public:intr;intArea(){return3.14*r*r;}};classB{publ

classCircle{protecteddoubleradius;publicCircle(){radius=0;}publicCircle(doubleradius){thi

classcircle{floatradius;floatarea;public:circle(floatr){radius=r;}floatgetarea(void){area=3.14*radiu

把这三个类分别放到三个.java文件中,然后编译运行即可.publicclassCircle{privatedoubler;publicCircle(doubler){this.r=r;}public

#includeusingnamespacestd;#definePI3.14classPoint{public:\x09Point():m_x(0),m_y(0){}\x09Point(double

classcircle{public:circle(){radius=0;}circle(doubleradiuv){radius=radiuv;}voidgetparimeter(){parimet

#includeusingnamespacestd;classCircle{public:Circle(doubler=0):radius(r){}doubleArea(){return3.14*ra

publicclassCircle{privatedoubleradius;publicCircle(doubler){this.radius=r;}publicstaticvoidmain(Stri

用VB程序设计做的随机画十个圆的编程代码（抱歉：就知道这些）Dimr(10)AsInteger,iAsInteger'半径Dimx(10)AsInteger,nAsInteger'半径坐标Dimy(1

classCircle{privatedoubleradius;publicCircle(){this.radius=0;}publicCircle(doubler){this.radius=r;}p

#includeclasscircle{private:intr;public:voidinput(){cout

#include#definePI3.14159usingnamespacestd;classcircle{private:doubleRadius;public:voidjiandan();};vo

不要提出这种问题,代码还是自己动手写的好,写的过程中遇到麻烦,再拿出来问的话,我想会有更多人乐意帮你解答的再问：来不及哦！！今天晚上要交！！没时间慢慢写！！我对c++也不是很熟！急求高手流利的给个程序

Console.WriteLine("请输入圆的半径");intr=int.Parse(Console.ReadLine());doublecircle=2*3.14*r;doublearea=3.1

#include <iostream>using namespace std;const double PI = 3.

根据题意实现代码如下：#include <iostream>#include <cmath>#include <string>usin