计算X除以Y分之X.X分之1-搜答案-拍题作业网

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²

(1)[1+(x-2分之1)]除以(2x-4)分之(x^2-1)=(x-1)/(x-2)*2(x-2)/(x+1)(x-1)=2/(x+1)[等于(x+1)分之2](2)[(x-y)^2+3(x^2-

x的平方-9分之1-x-3分之1除以x-1分之6+2x=1/(x^2-9)-1/(x-3)*(x-1)/2(3+x)=(2-(x-1))/2(x^2-9)=(3-x)/2(x^2-9)=-(x-3)/

(根号y分之x-根号x分之y)除以（根号y分之1-根号x分之1）=[(x-y)/根号xy]÷[（根号x-根号y)/根号xy]=根号x+根号y

=3xy×(-3x/2y)=-9x²/2

1.计算：x-y分之x+y+y-3分之2x=(x+y)/(x-y)+2x/(y-3)=((x+y)(y-3)+2x(x-y))/(x-y)(y-3)=(xy-3x+y^2-3y+2x^2-2xy)/(

计算：x-y分之x×x+y分之y的平方-x的4次方-y的4次方分之x的4次方y除以x的平方+y的平方分之x的平方=x/x-y分之x×y^2/x+y-x^4y/(x^4-y^4)*(x^2+y^2)/x

原式=(x-x²+x-1)/x÷(x+1-1)/(x+1)=-(x-1)²/x*(x+1)/x=-(x-1)²(x+1)=-(x-1)(x²+1)=-x

1、(xy分之x²-y²)×(x-y分之x)-(y分之x)；=(x+y)(x-y)/xy×x/(x-y)-x/y=(x+y)/y-x/y=(x+y-x)/y=12、6xy²

（1）=x平方-y平房分之x(x+y)-y(x-y)+2xy=（x+y）*（x-y）分之（x+y）的平方=x-y分之x+y（2）=a-1分之2-a-1分之a+1=-1

[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x

[3x分之2-（x+y分之2）乘以[3x分之x+（y-x^2-xy）]除以x分之x-y{2/3x-2/(x+y)*[x/3x+(y-x²-xy)]}÷(x-y)/x题目错了吧?再问：{3x分

[x+1分之x]-[2x2-1分之2]=1再问：��̣�лл��

[1]y+2分之y的平方-6y+9除以[3-y]=（3-y)²/(y+2)×/(3-y)=(3-y)/(y+2)[2]x的立方分之x的平方y乘以[-y分之1]=x²y/x³

你是不是觉得这种题很简单啊?再问：我对一下答案，我不确定再答：0分，我嫌麻烦再问：可以吗再答：算了，我不是要饭的2x/(2x-y)+y/(y-2x)*(x-1)²/(x+1)(x-1)*x(

现将括号里的通分x2-y2可约去最后的y分之2再问：能具体一点吗再答：原式=((x+y+x-y)/(x2-y2)÷（x的平方-y的平方分之xy）=2x/(x2-y2)×(x2-y2)/xy=y分之2只

原式=5x根号(xy)/3根号(y/x)*1/3根号(x/y)=5/9*根号(xy*x/y*x/y)=5x/9y根号(xy)

是这样的形式吗?[x/（x+y）+2y/（x+y）]×[xy/（x+y）]÷（1/x+1/y）一:原式=（x+2y）/（x+y）×[xy/（x+2y）]÷[（x+y）/xy]=x²y&sup