计算2n的阶乘C语言-搜答案-拍题作业网

#includeintmain(){doublefac;doublesum;intn;inti;sum=1.0;n=10;fac=1;printf("sum=1");for(i=0;i

#includelongfactorial(intm,intn){longsum=1,sum1=1;inti;if(m-n>n){for(i=m;i>m-n;i--)sum*=i;for

1：n>12：n-13：n我认为题有点问题3应该就是return1-----------------------------------------longfun(intn){if(__1__)ret

intjc(intx){returnx==1?1:jc(x-1)*x;}再问：可以编一个完整的么？我直接运行试一下。。。新手，不好意思，，，，谢谢再答：intjc(intx){returnx==1?1

#includemain(){inti,j,n;floatsum=0;scanf("%d",&n);for(i=1;i

#include "stdio.h"double fun(int n)//用double提高精度和计数位数.{ double&n

#include <stdio.h>int main(){\x09int n,i,sum=1;\x09scanf("%d",&n)

1.输入整数N2.若N

#include#include#includevoidmain(){longintsum1=1;longintsum=0;inti=0;intnu=0;scanf("%d",&i);while(i!

#includemain(){\x09\x09longi,n=1;\x09for(i=1;i

intfactorial(intn){if(n

#include<stdlib.h\x0d#include<iostream\x0d#include<iomanip\x0dusingnamespacestd;\x0dconstin

输入的a不能太大,否则整型会溢出的!#includemain(){inta,b,c,s,t;s=1;t=0;//1----->0scanf("%d",&a);for(c=1;c

#includevoidmain(){intn,i,k=1,sum=0;scanf("%d",&n);for(i=1;i

刚才刚弄过一个,int数组每个元素保存四位数,10000以内的阶乘不会有问题#include#defineN10000intmain(){\x09staticlongintr[N]={1};/*用lo

你这个没有输出啊!要输出那个值啊!还有if(a=0)改为if(a==0)#includeintx;intsum(inta){intk;if(a==0)k=1;elsek=x*sum(a-1);retu

clearinput"n="tons=1fori=1tons=s*iendfor"n!=",s

#include#includefun(intx);intmain(void){char*pszBuff=NULL;inta;inti=1;intsumResult=0;printf("inputai

#includeintf(intn){if(n

#includeintmain(){inta,i,n;scanf("%d",&n);/*这里*/a=1;i=2;while(i再问：谢谢你，方便留个QQ么？我是个新手，学C语言是摸石头过河的，想找个师