计算(x² nx 3)(x²-3x)
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当x=-2时,y=m•(-2)5+n•(-2)3+p(-2)-7=5,则-25m-23n-2p-7=5,-25m-23n-2p=12,当x=2时,y=25m+23•n+2p-7,两式相加:y=-12-
==(x+3)(x-2)(x+1)再问:嗯就是想问下最后结果是……?00再答:(x3-x2-2x+3x2-3x-6=x3+2x2-5x-6(x后的数字表示次数)
原式=x2+2x+4(x+2)2÷(x−2)(x2+2x+4)3(x+2)÷1(x+2)(x−2)=x2+2x+4(x+2)2•3(x+2)(x−2)(x2+2x+4)•(x+2)(x-2)=3.
解-x²(-x)³+3x³(-x²)-4(-x)(-x)^4=x^5-3x^5+4x^5=(1-3+4)x^5=2x^5
=x²+3x-(x²-3x+2)=x²+3x-x²+3x-2=6x-2
x2x−5+255−x=x2x−5-25x−5=x2−25x−5=(x+5)(x−5)x−5=x+5,故答案为:x+5.
原式=[x/x(x-3)](x+3)(x-3)=(x+3)(x-3)/(x-3)=x+3
x=8+b/a-4x=1/m-nx=10mn/4m-3x=8+b/a-41、原式可化为:x=2001/(k+1)2001的约数有1、3、23、29、69、87、667、2001,所以k可以等于0、2、
(x^2+5x+4)(x^2+5x+6)=(x^2+5x)^2+10(x^2+5x)+24=x^4+10x^3+35x^2+50x+24
(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-
(x+1)(x-2)(x-3)(x-6)==(x+1)(x-6)(x-2)(x-3)=(x^2-5x-6)(x^2-5x+6)=(x^2-5x)^2-36=x^4-10x^3+25x^2-36
原式=[x/(x-3)]-[5x/(x²-x-6)]=[x/(x-3)]-(5x)/[(x-3)(x+2)]=[x(x+2)]/[(x-3)(x+2)]-(5x)/[(x-3)(x+2)]=
x/(x^2-1)+(x^2-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)-2x^3/(x^4-1)=x/(x^2-1)-2x^3/(x^4-1)+(x^2-x
3x/(x-5)-2x/(5-x)=3x/(x-5)+2x/(x-5)=5x/(x-5)
2x*4x-3x=8x平方-3x
原式=(x−2x+2-xx+2)•x+2x−1=−2x+2•x+2x−1=−2x−1.
原式=(x+3)(x-2)(x+1)
(X-1)(X-2)(X-3)(X-4)=(X-1)(X-4)(X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25
由原式=3/x+x/(x+1)(x-1)+4/(x-1)=[3(x²-1)+x²+4(x²-1)]/x(x+1)(x-1)=(4x³+4x²-4x-3