解方程:5(x-4)-3(2x 1)=2(1-2x)-1解:去括号,得____,
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 10:32:58
乘出来3x³+5x²+5=-x³+4x³+5x²+x3x³+5x²+5=3x³+5x²+x两边减去3x
(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么
-x(3x-2)+2x(2-x)=-5x(x-2)-4-x(3x-2)+2x(2-x)+5x(x-2)+4=0-3x^2+2x+4x-2x^2+5x^2-10x+4=0-4x+4=0-4x=-4x=1
((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30
4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~
x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1
原式5/X(X-2)-4/X(X+2)=3/X²-45(X+2)/X(X-2)(X+2)-4(X-2)/X(X-2)(X+2)=3/X²-4(5X+10)/X-(4X-8)/X=3
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
再问:2x是怎么得来的
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x
2x的平方-6x-4x+3x的平方=5X²-3X+2-7x=2x等于负七分之二
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1
(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1
2x^2-6x-4x+3x^2-5x^2+3x-2=0-7x=2x=-2/7
此方程要分两种情况,当X=2时,方程左边=右边,显然X=2是方程的解.当X不等于2时,那X-2就不等于0,所以它可以约掉.那么有5X-(X+4)=2(2X-3)去掉括号后4X-4=4X-6,方程无解,