解方程1 x-7 1 x-1=x-6 1 x-2

7/x²+x+6/1-x²=1/x-x²两边同乘以x(x+1)(x-1),得7x-7-6x=-x-12x=6x=3经检验x=3是方程的根.

(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)x^3+x^2+x-6x^2-6x-6-x^3+x=2x-5x^2-4x-6=2x6x=-6x=-1

两边乘(x+3)(x-2)6x+18=x²-2x-x²-x+66x+18=-3x+69x=-12x=-4/3经检验,x=-4/3是方程的解

解x(6-x)-2x(x+1)-(x³-3x^4)/x²=46x-x²-2x²-2x-(x-3x²)=44x-3x²-x+3x²=

4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

我给个思路吧（X+2-1/X+2)-(X+3-1/X+3)=（X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决

是X/（X-2）-（1-X^2）/（X^2-5X+6）=2X/（X-3）吗?首先因式分解（X^2-5X+6）=（X-2）（X-3）,显然X不等于2且X不等于3,所以等式两边同乘以（X-2）（X-3）得

(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)

2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99

解方程两边同时乘以x(x-1)(x+1)得：(x+1)+7(x-1)=6x即8x-6=6x2x=6∴x=3经检验x=3是方程的解

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

7/(x^2+x)+3/(x^2-x)=6/(x^2-1)7/x(x+1)+3/x(x-1)=6/(x-1)(x+1)分子分母同乘以x(x-1)(x+1),得7（x-1）+3（x+1)=6x10x-4

通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

两边乘以x(x+1)(x-1)得7x-7+4x+4=6x5x=3x=3/5检验：x=3/5是方程的解∴方程的解为x=3/5

1/x(x+3)+1/(x+3)(x+6)-1/3x=11/(x+3)*[1/x+1/(x+6)]-1/3x=11/x+1/x+6-(x+3)/3x=x+31/x+1/(x+6)-1/3-1/x=x+

你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/