解3(x-1)²-12=0-搜答案-拍题作业网

两边乘以(x+1)(x-1)得x²-3x+(2x-1)(x+1)=0x²-3x+2x²+x-1=03x²-2x-1=0(3x+1)(x-1)=0∴x=-1/3x

1,（1）将（x+3/x-1）设为a（2）得a²-5a+6=0（3）因式分解（a-2）（a-3）=0（4）a1=2a2=32,化简得x³-4x²+18=0

4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~

题目有点问题,应是(x²+3x+1)/(4x²+6x-1)-(12x²+18x-3)/(x²+3x+1)=2(x²+3x+1)/(4x²+6

解方程：196x平方-1=0196x^2=114x=±1x1=1/14x2=-1/144x平方+12x+9=81(2x+3)^2=812x+3=±9x1=3x2=-6x平方-7x-1=0(x-3.5)

2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0

1.(3x-1)^2-4=0(3x-1+2)(3x-1-2)=03x+1=0或3x-3=0则x=-1/3或x=12.2x(x-1)-x(3x+2)=x(x+2)-122x^2-2x-3x^2-2x=x

方程两边同时乘以x²-1:(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=03x^3+9x^2+7x-3x^2-9x-7-(2

(x+1)(x+2)(x^2-2x-1)(x-3)(x-4)+24=0(x+1)(x-3)(x+2)(x-4)(x^2-2x-1)+24=0(x^2-2x-3)(x^2-2x-8)(x^2-2x-1)

2/x^2+x+3/x^2-x-4/x^2-1=0(2/x^2+3/x^2-4/x^2)+x-x-1=01/x^2-1=01/x^2=1x^2=1x=1或-1

1、4x²+x+10=1-8x4x²+9x+9=0▲=√9²-4×4×9=√-63（无意义）∴方程无解2、x²/4-2x-12=0x²-8x-48=0

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

（x+6)²-9=0(x+6)^2=9x+6=±3x=-3或-9x^2-2x+1=25(x-1)^2=25x-1=±5x=6或x=-44x^2+12x+9=81(2x+3)^2=812x+3

（1）7/(x^2-x-4)=0???应该是(x^2-x-4)/7=0即求x^2-x-4=0x=[-b+根号(b^2-4ac)]/2a或x=[-b+-根号(b^2-4ac)]/2a,前提是(b^2-4

应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x

用换元法设x*x+11x-8＝A然后再做

解(x+1)(x-3)=12

解方程：x*x+12x-3=0

用求根公式,配方法

=x^2002(x^4+x^3+x^2+x+1)=0提取公因式就行了

3x²=10x+83x²-10x-8=0x=(10±√(100+4×3×8)/2*3x=(10±√196)/6x=(10±14)/6∴x1=4x2=-2/33x²-10x