若方程2x-7-3x∣4=2-5x-1∣6同解,求M的值-搜答案-拍题作业网

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30

4x/(x^2+2x+4)-3x/(x^2-3x+4)=-7/3分母不为0,x^2+2x+4和x^2-3x+4均不为0通分x（x^2-18x+4)/(x^2+2x+4)(x^2-3x+4)=-7/3再

x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1

(x²-x+4)x-(x-1)(x²+2)=x+7x³-x²+4x-x³+x²-2x+2=x+72x+2=x+72x-x=7-2x=5

解方程：7x-2x+3x=36

7x-2x+3x=365x+3x=368x=36x=4.5

再问：2x是怎么得来的

方程两边同时乘以x²-1:(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=03x^3+9x^2+7x-3x^2-9x-7-(2

3x【7-2x】+5x【2x-1】=4x【x-3】+5621x-6x^2+10x^2-5x=4x^2-12x+5628x=56x=2x的n次方【x的n次方+9x-12】-3【3x的n+1次方-4x的n

通分得[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),

(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[（x-8）(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(

21x-6x^2+10X^2-5x-4x^2+12x-56=028x-56=0x=21/9x^2y^2*(2yx^2-xy^2-2yx^2+2xy^2)=(1/9x^2y^2)*xy^2=1/9x^3

解方程7x-2x+3x=36

（7-2+3）X=368X=36X=9/2

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1

2(x-3)(x+5)=x^2+(x+2)(x-2)+(x+7)2(x^2+2x-15)=x^2+x^2-4+x+72x^2+4x-30=2x^2+x+33x=33x=11

(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1

解题思路：高次方程的解法分解因式解题过程：

你那是3乘啊还是3X?再问：3X再答：21X-6X`2+10X`2-5X=4X`2-12X+5628X=56X=2

1,应该是x是几次幂就有几个根吧,所以应该是7+2=9个2.-7.036622145,-6.489288572,-6.200988153,-4.734373320,-4.289168546,-2.77