若x=2y-5,求5(x-2y)2 6y-3x的值

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如果x,y表示有理数,且x、y满足条件,|x|=5,|y|=2.|x-y|=y-x,求:x+2y的值.

有题可知,y≥X,所以y=±2,X=-5,y=2,X=-5,x+2y=-1;y=-2,X=-5,x+2y=-9a=3的55次方=3的5次方再11次方=243的11次方b=4的44次方=4的4次方再11

若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

若x^5+x^4y+x^4+x+y+1=0,且3x+2y=1,求x,y的值

x^5+x^4y+x^4+x+y+1=0x^4(x+y+1)+x+y+1=0(x^4+1)(x+y+1)=0然后因为x^4+1不可能等于0所以只有x+y+1=0x+y+1=03x+2y=1这两个公式,

已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值

∵x²+y²-4x+2y+5=0x²-4x+4+y²+2y+1=0(x-2)²+(y+1)²=0x-2=0y+1=0∴x=2y=-14x&#

(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²

(1)已知x+y=6,x²-y²=5,x^2-y^2=(x+y)(x-y)=5x-y=5/(x+y)=5/6(2)若x+y=3,x²+y²=5(x+y)^2=3

若实数x、y满足x平方+y平方-4x-2y+5=0,求根号8y-2x分之(根号x)+y

x平方+y平方-4x-2y+5=0(x-2)^2+(y-1)^2=0(x-2)^2=0(y-1)^2=0x=2y=1根号8y-2x分之(根号x)+y=(根号2)+1/根号(8*1-2*2)=[(根号2

求y''-2y'+5y=(e^x)sin2x

咋不是特征根了根据你解得的齐次的通解是y=e^x(C1sin2x+C2cos2x)右边含在齐次特解里再问:1.加减号打的时候打错了~2.由特征方程得出的解是含有复数,我知道可以是复数。3.这个我也知道

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

若实数x,y满足x^2+y^2-4x-2y+5=0,求(√x+y)/[√(8y-2x)]

(x²-4x+4)+(y²-2y+1)=0→(x-2)²+(y-1)²=0→x=2,y=1原式=(√2+1)/2

已知x^2+4y^2-4x+4y+5=0,求(y^4-x^4)/(y-2x)(x+y)*2x-y

已知x^2+4y^2-4x+4y+5=0求((y^4-x^4)/(y-2x)(x+y))*((2x-y)/(xy-y^2))/((x^2+y^2)/y)的值答案:x²+4y²-4x

若[x-y]+[y-5]=0,求2x+y.[ ]表示绝对值的符号

x-y的绝对值+y-5的绝对值=0满足上式的条件是x-y=0y-5=0解得x=y=5故2x+y=2*5+5=15

若x-y/x+y=5,求x-y/2x+2y+5x+5y/3x-3y的值

若x-y/x+y=5则x-y=5(x+y)所以求x-y/2x+2y+5x+5y/3x-3y=5(x+y)/[2(x+y)]+5(x+y)/3(x-y)=5/2+5(x+y)/[3*5(x+y)]=5/

若x、y、z满足2x+3y+z=18,4x-3y+5y=24,求x+3y的值.

2x+3y+z=18(1)4x-3y+5y=24(2)(1)*5-(2)10x+15y+5z-4x+3y-5z=90-246x+18y=66x+3y=11

已知x²+y²+5=2x+4y,求代数式(2x²-(x+y)(x-y))x((x+y-1)

已知x²+y²+5=2x+4y所以(x-1)²+(y-2)²=0故x=1,y=2所以(2x²-(x+y)(x-y))×((x+y-1)(x-y+1)+

1.当x,y为何值时,代数式-x*x-2y*y-2x+8y-5有最大值,求最大值.2.若x*x+y*y+5/4=2x+y

1、-x*x-2y*y-2x+8y-5=-(x^2+2x+1)-2(y^2-4y+4)+4=-(x+1)^2-2(y-2)^2+4≤4当且仅当x=-1,y=2时,有最大值42、x*x+y*y+5/4=

求dy/dx=(x-y+5)/(x+y-2)

dy/dx=(x-y+5)/(x+y-2)=[(x+3/2)-(y-7/2)]/[(x+3/2)+(y-7/2)]令v=y-7/2,u=x+3/2,原方程化为dv/du=(u-v)/(u+v)变为齐次

若2x-3y=0,求5x+4y/3x-2y

2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6

已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y

1,-3再问:过程。。。再答:★(x²-2x)+(y²-4y)=5★(x-1)²+(y-2)²=1+4-5★(x-l)²=0,(y-2)²=

已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009)y=0+(1×1004-2009)y=-1005y=1005/2