若x-2y=8,x+2y=6
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联立x−y=6x+y=8,解得x=7y=1,所以7a+2=b7+a=3,解得a=−4b=−26,所以,a、b的值为:a=-4,b=-26.
2X+3Y-1=X+62X+3Y=7(1)Y-X-8=X+62X-Y=-14(2)(1)+(2)4X+2Y=-7两边除以22X+Y=-7/2
3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)
(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x
1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2
-8(2x-y)-{7x-[6x+2y-(10x-8y)]}=-16x+8y-[7x-(6x+2y-10x+8y)]=-16x+8y-(7x-6x-2y+10x-8y)=-16x+8y-7x+6x+2
(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢
方法一:(1)×2-(2)得:3y=3,y=1.将y=1代入(1)得:x+2=6,x=4.∴x+y=1+4=5x+y=5.方法二:两个方程相加,得3x+3y=15,x+y=5.
由题意得:y-x-8=x+6,将其变形得:2x-y=-14.
(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)=(x+y)²+2z(x+y)+z²+(x-y)²-z²-2z(x+y)=(x+y)&
2x+3y-1=x+6-----(1)y-x-8=x+6----(2)以上方程组分别移项,消元得:x=7-3y-----(3)y=14+2x-----(4)将以上(3)代入(4)式,解得:y=4再将y
x平方+8x+16+y平方+6x+9=0(x+4)平方+(y+3)平方=0∴x+4=0y+3=0∴x=-4,y=-3原式=(x+2y)(x-2y)/(x+2y)平方-x/(x+2y)=(x-2y)/(
X+6=Y-X-8,所以2X-Y+14=0;Y-X-8=2X-3Y-1,所以3X-4Y+7=0;联立,可得X=-119/10;Y=-49/5再问:那3X-Y?再答:下面你不会吗?3X=-357/10,
若(x-y)/(x+y)=3那么x-y=3(x+y)x-y=3x+3y故x=-2y所以(x+2y)/(6x-7y)=(-2y+2y)/(6*(-2y)-7y)=0如果不懂,请Hi我,祝学习愉快!
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y=(y^2-4x^2+4x^2+16xy+16y^2)/3y=(17y^2+16xy)/3y=17y/3+16x/32.(2(x-y)^3-
等于.-3y-10x
x+3y+|3x-y|=192x+y=6可知y=6-2x:代入上式可得x+3(6-2x)+|3x-(6-2x)|=19化简计算后可知:|5x-6|=1+5x可知5x-6=1+5x或5x-6=-(1+5