MATLAB求Dx 2*Dx x=sin(t),x(0)=1,Dx(0)=1得值
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X=arctantdx/dt=1/(1+t^2)y=ln(1+t2)dy/dt=2t/(1+t^2)dy/dx=(dy/dt)/(dx/dt)=2td2y/dx2=d(dy/dx)/dx=2dt/dx
(1)令x=0,ax5+bx4+cx3+dx2+ex+f=f=-1.(2)令x=1,ax5+bx4+cx3+dx2+ex+f=a+b+c+d+e+f=1,∴a+b+c+d+e=2①;(3)令x=-1,
1.dy/dx=(dy/dt)/(dx/dt)=(3t^2-3)/(2-2t)=-3/2*(t+1)2.a(t)=s''(t)=((e^t-(-1)e^-t)/2)'=(e^t-e^-t)/2=s(t
1、利用圆的正余弦函数,令X=aCOSθ;Y=aSINθ,所以dy/dx=(dy/dθ)/(dx/dθ)=acosθ/(-asinθ)=-ctgθ=-x/y;2、由y=a^x可得X=LOGay,对式子
1、原式=∫(sinx^2)*(cosx^2)dsinx=∫sin^2*(1-sinx^2)dsinx=∫(sin^2-sinx^4)dsinx=∫sinx^2dsinx-∫sinx^4dsinx=1
令p=dy/dx,则d^2y/dx^2=dp/dy*dy/dx=pdp/dy代入原方程:pdp/dy=Acosy即pdp=Acosydy积分:p^2/2=Asiny+C1得:p=±√[2Asiny+C
Lz问的可能是教材中反函数的2阶导数公式:(满足一定条件的)函数y=y(x)的反函数是x=x(y),于是有dx/dy=1/(dy/dx)=1/y';则(d^2x)/dy^2=(d/dy)(dx/dy)
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d2y/dx2=d(dy/dx)/dx=d(y'(t)/x'(t))/dx(t)=(y''(t)x'(t)-y'(t)x''(t))/x'3(t)附:d(y'(t)/x'(t))=(y''(t)x'(
1、令x=0则右边ax的五次幂+bx的四次幂+cx3+dx2+ex,每项都是0所以右边=f左边是(0-1)的五次幂=-1所以f=-12、令x=11的任意次幂都是1所以右边=a+b+c+d+e+f左边等
∵(x+2)5=ax5+bx4+cx3+dx2+ex+f,令x=-2,有0=-32a+16b-8c+4d-2e+f①令x=2,有1024=32a+16b+8c+4d+2e+f②由②+①有:1024=3
(1)(x+1)5,=(x+1)2×(x+1)2×(x+1),=(x2+2x+1)(x2+2x+1)(x+1),=(x4+4x3+6x2+4x+1)(x+1),=x5+5x4+10x3+10x2+5x
x=-2:0.1:2;y=x;[x,y]=meshgrid(x,y);z=x.*y;surf(x,y,z);grid on;xlabel('x.axis');ylabel(&
再问:我等号后面是ln,你给的是log,为什么答案会一样...再答:我打错了..应该是ln哈哈
dsolve('D2y+w^2*sin(x)','x')
用数值解[t,x]=ode45('hopema',[03],[0;2]);plot(t,x)-------------------------------------functiondx=hopema
1题,2(y-1)dy=dxdy/dx=1/(2(y-1))2题,arcsiny=(x+y²)-½x+y²=(arcsiny)²dx+2ydy=2arcsi
dx/dt=2t/(1+t²)dy/dt=1/(1+t²)dy/dx=1/(2t)d(dx/dt)/dt=(2-4t²)/(1+t²)²d(dy/dt
应该是求的d2y/dx2吧,这个不能求d2y/d2x