m>n>0 m^2 n^2=4mn

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已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值

(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)先去括号=2mn+2m+3n-3mn-2n+2m-m-4n-mn合并同类项=-2mn+3m-3n=-2mn+3(m-n)把m-n=2,

已知m-n=4,mn=2,求多项式(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.

解(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=-2mn-3mn-mn+2m+2m-m+3n-2n-4n=-6mn+3

设m>n>0,m^2+n^2=4mn,则(m-n)^2/mn的值等于

m²+n²=4mnm²+n²-2mn=4mn-2mn(m-n)²=2mn(m-n)²/mn原式=2mn/mn=2【中学生数理化】团队wdxf

若m-n=4,mn=-1求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)

先合并同类项,得3(m-n)-6mn+9,代入已知数据,有结果27

已知|m+n-2|+(mn+3)^=0,求2(m+n)-2[mn+(m+n)]+3[2(m+n)-3mn]的值

|m+n-2|+(mn+3)^=0必然M+N-2=0MN+3=0即M+N=2,MN=-3所以2(m+n)-2[mn+(m+n)]+3[2(m+n)-3mn]=2*2-2{-3+2]+3[2*2-3*(

若m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值

(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=(-2mn-3mn-mn)+(2m+2m-m)+(3n-2n-4n)=-

已知√m-n +√3m-2n=0,求4m²-mn+6n²-2m²+6mn-10n²

算术平方根大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.所以两个都等于0所以m-n=03m-2n=0所以m=0,n=0所以原式=2m²+5mn-4n²=0+0-0

已知|m+n-2|+(mn+3)的平方=0,求3(m+n)-2[mn+(m+n)]-3[29m+n)-3mn]的值

由已知条件知:m+n=2,mn=-3.代入得:所求的式子的结果是:-31PS:我觉得你的问题是:3(m+n)-2[mn+(m+n)]-3[2(m+n)-3mn].

已知m-n=3,mn=-1,求多项式-2mn+2m+3n-3mn-2n+2m-4n-m-mn的值

-2mn+2m+3n-3mn-2n+2m-4n-m-mn=-6mn+3m-3n=-6mn+3(m-n)=6+9=15

已知丨m+n-2丨+(mn+3)的平方=0,求3(m+n)-2【mn+(m+n)】-3【2(m+n)-3mn】的值

m+n-2=0;mn+3=0;3(m+n)-2【mn+(m+n)】-3【2(m+n)-3mn=3×2-2(-3+2)-3(2×2+9)=6+2-39=-31;很高兴为您解答,skyhunter002为

若m,n为有理数,且2 m^2-2mn+n^2+4m+4=0,则m^2n+mn^2=

2m^2-2mn+n^2+4m+4=0(m^2-2mn+n^2)+(m^2+4m+4)=0(m-n)^2+(m+2)^2=0等式成立的条件为:m-n=0m+2=0所以m=n=-2m^2n+mn^2=m

1+n-m/m+2n÷m²-n²/m²+4mn+4n²=

你好!数学之美团为你解答1+(n-m)/(m+2n)÷(m²-n²)/(m²+4mn+4n²)=1+(n-m)/(m+2n)×(m+2n)²/[(m+

已知m-n=4,mn=2,求多项式(-2mn+2m+3n)-(3mn+2n-2n)-(m+4n+mn)的值

原式=-2mn+2m+3n-3mn-2n+2n-m-4n-mn=-6mn+m-n=-6×2+4=-8

|m+n-2|+(mn+3)^=0,求3(m+n)-2[mn+(m+n)]-3[2(m+n)-3mn]的值

|m+n-2|+(mn+3)²=0,则m+n-2=0且mn+3=0,得:m+n=2,mn=-3从而,3(m+n)-2[mn+(m+n)]-3[2(m+n)-3mn]=3(m+n)-2mn-2

若m-n=4,mn=-1,求(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)的值

已知mn=-1,m-n=4则(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)=-2mn+m+n-3mn-5n+5m-m-4n+3mn=-2mn+5m-8n=2+20-3n=22-3n

若m+n=0,则多项式m^3-m^3n-mn^2+n^3

题错了应该是m^3-m^2n-mn^2+n^3=m^3+n^3-mn(m+n)=m^3+n^3-0=(m+n)(m^2-mn+n^2)=0

已知m-n=3,mn=-3,求(-m-4n-mn)-(2mn-2m-3n)-(3mn+2n-2m)的值

(-m-4n-mn)-(2mn-2m-3n)-(3mn+2n-2m)=-m-4n-mn-2mn+2m+3n-3mn-2n+2m=3m-3n-6mn=3(m-n)-6mn=3×3-6×(-3)=9+18

规定新运算:m#n=m+n,m﹡n=m-n,试化简[(mn²﹚#(2mn)]+[(4mn²)﹡(3m

原式化简=mn²+2mn+4mn²-3mn=5mn²-mn注:[(mn²﹚#(2mn)]=mn²+2mn因为m#n=m+n同理后面的一样带入值运算得1

知m*m-mn=1,4mn-3n*n=-2,则m*m+3mn-3n*n的值是多少

m^2-mn=14mn-3n^2=-2m^2+3mn-3n^2=(m^2-mn)+3mn-3n^2+mn=1+4mn-3n^2=1-2=-1