编程计算3 33 ...3(n个3的值)

intn,sum=0;cin>>n;for(inti=1;i

N>200也就是说最后一个是201*202,总共是201项相加.movbx,1movdx,0movah,2movcx,200s:moval,ahincahmovsi,axmulahaddbx,axad

你自己写点,有问题我帮你调试.这个不难再问：不会写啊再答：编程就是个熟练活儿，多练习就会了# include <stdio.h>int main(void){

#includevoidfun(long*num,intnn);intmain(){intn;longsum=0;cout再问：调试了好像有点问题再答：#includevoidfun(long*num

分呢?程序给你下次记得给分啊!//用c语言,编程计算a+aa+aaa+…+aa…a〔n个a〕的值,其中a是一个数字,n键盘输入.n=5,a=3#includeintpow(intx,inty)//x的

intfun(inta,intn){inti,r=0,t;t=a;for(i=1;i

#include<stdio.h>intmain(){longN,t=1,sum=0,i;label:printf("pleaseinputN(n>1&&n<1

#includevoidmain(){longi,n,num=1,result=0;printf("Pleaseinputanum:");scanf("%ld",&n);for(i=1;i

#includeintmain(){inti=0;floatsum=0;intn;intx[n],y[n];printf("请输出计算的项数:");scanf("%d",&n);x[0]=2;x[1]

programt1;vari,j,k2,k5,m,n:longint;beginreadln(n);fori:=1tondo{每个数的质因数2和5的个数的循环}beginm:=i;whilemmod2

#includelongcountNum(intn){longnum=1;intm=n;while(m){num*=m--;}returnnum;}longcountSum(intn){longi=0

functionCalculateE(n:integer):real;//计算n项,返回e的近似值varm,e:real;//为了防止阶乘太大而溢出,把m改用real变量.i:integer;begi

publicf(byvalnasinteger)aslongifn=1thenf=1elsef=f(n-1)+nendifendfunction

S=1!+2!+3!+…+n!,得n!=n*(n-1)*(n-2)*…*2*1

这不是数学么,总结出通项就行了.intn=5；//定义要循环的次数doublesum=0;for(inti=1;i

clearinput"n="tons=1fori=1tons=s*iendfor"n!=",s

用for循环计算inta=2;ints=0;for(inti=1;i

publicclasssum{/***@paramargs*/publicstaticvoidmain(String[]args){//TODOAuto-generatedmethodstubintn

PrivateSubForm_Click()DimsAsLongDimt1AsLongs=0Fori=1Tont1=1Forj=1Toit1=t1*jNexts=s+t1NextPrintsEndSu

那用C语言写给你看看#include"stdio.h"main(){intn,k=-1;/*K作为加减的转换*/doubles=1;输入n的代码我就不说了for(i=1;i