编程由键盘输入一个三位数,要求按逆序输出各位数字

voidmain(){inta[10];intmax=0;inti;for(i=1;ia[max])max=i;}if(max!=0){i=a[0];a[0]=a[max];a[max]=i;}/*最

应该用fabs的,abs是求整数的,fabs是求小数的,C语言很简单的,不需要题库,把书上的习题和例题的代码自己敲一遍就ok

stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons

n=val(inputbox"请输入一个数字.")fori=1tona=a+inextiprinta

1#include"stdio.h"main(){intn,i;scanf("%d",&n);printf("%d",n/100+n%100/10+n%10);system("PAUSE");}2#i

#include"stdio.h"//voidmain(void){inta,b,c;printf("请输入两个十进制整数!\na=");scanf("%d",&a);printf("b=")

程序的实现的是这样的,先设置一个文本框,用于n值的出入.再设置一个命令按钮用于求解.代码如下：PrivateSubCommand1_Click()DimnAsInteger,iAsInteger,mA

#include#definek3intmain(){intenter;//intk=3;intarr[k][k];inti,j,sum=0;for(i=0;i

programt1;vari,j,k2,k5,m,n:longint;beginreadln(n);fori:=1tondo{每个数的质因数2和5的个数的循环}beginm:=i;whilemmod2

兄弟,啥语言嘛?不说语言单说要求有啥用啊?再问：c语言再答：#include#includestructstu{intgrade1,grade2,grade3,count,average;stu*ne

PrivateSubCommand1_Click()DimaAsDouble,bAsDouble,cAsDoubleDimpAsDouble,SAsDoublea=InputBox("a?")b=In

#include#includeintmain(){floata,b;printf("plesaseenteranumber\n");scanf("%f",&a);if(a>=1000){printf

这是我们以前做过的课后习题...#includevoidmain(){intn,i;floats=0,t=1;scanf("%d",&n);for(i=1;i

#includevoidmain(){intnum;printf("输入一个3位数:\n");scanf("%d",&num);printf("个位:%d\n十位:%d\n百位:%d\n",num%1

#includevoidmain(){inti,j,n;printf("请输入n的值：\n");scanf_s("%d",&n);for(i=1;i

#includeintk;voidshow(){chara;printf("Pleaseinputtheletter.\n");scanf("\n%c",&a);printf("Theletter's

给你个可以加减乘除的!#includevoidmain(){floata,b;charc;printf("\n");scanf("%f%c%f",&a,&c,&b);if(c=='+')

PrivateSubUserForm_Click()DimiAsInteger,jAsInteger,nAsInteger,rAsIntegern=Val(InputBox("n=","输入行数"))

main()　　{inta,b,c;　　printf(“请输入三个整数：”);　　scanf(“%d,%d,%d”,&a,&b,&c);　　if(aif(belseprintf(“max=%d\n”,

intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(