编写程序:输入x,计算并输出

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i

Subabc()'输入三角形三个边长,计算其面积Dima,b,c,sDos=InputBox("请输入三角形的三个边长,用半角逗号分隔."&Chr(13)&"输入-1时结束程序.")IfVal(s)=

给你写了个,运行通过,你看看吧,记得采纳哦O(∩_∩)O~#includeintmain(){\x09intnum,i=0;\x09printf("pleaseinputanumble:");\x09

1：#includeintmain(){intnum,sum=0;while(scanf("%d",&num)==1&&num>0){sum+=num;\x09}printf("结果为%d",sum)

首先C我长时间没碰了,但你的程序的问题还是能看出来的,还是看看书吧.main函数就不对,应是main(){程序主体}.if函数没有返回值,你的程序中没必要用这么多花括号,当if或else后只有一句条件

请编写一个程序,从键盘输入100名职工的职工号、姓名和工资,输出所有职工的#include

解题思路：赋值语句解题过程：varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph

#includevoidmain(){inta,b;printf("pleaseinputtwonums:");scanf("%d%d",&a,&b);printf("%d%d\n",a/b,a%b)

很简单的#includeusingnamespacestd;voidmain(){doublex,y;cin>>x;if(x

若梯形的上底为a、下底为b、高为h，面积为S，故程序语句如下：INPUT“梯形的上底，下底，高”；a，b，hS=（a+b）*h/2PRINT“正方形的面积为：”；SEND

elsey=3*x+1；后面的封号是汉字的

#include#definepai3.15149256voidmain(){doubler,c,s;printf("pleaseinputr\n")scanf("%lf",&r);printf("c

#include//希望对您有用#includeintmain(){intx,y;printf("Pleaseenterthenumber:");scanf("%d",&x);if(x

Dimi1AsIntegerDimi2AsIntegerDimi3AsIntegeri1=Val(InputBox("请输入第一个整数"))i2=Val(InputBox("请输入第二个整数"))i3

#includeusingnamespacestd;voidmain(){doublex,y,z;cin>>x>>y>>z;cout

voidmain(){floatx,y;cin>>x;if(x=10)y=3*x-11;elsey=2*x-1;cout

PrivateSubCommand1_Click()a=InputBox("请输入数字","提示")b=InputBox("请输入数字","提示")Print"和："&Val(a)+Val(b)Pri

#includemain(){floata,b,c;floatp,s;scanf("%f%f%f",&a,&b,&c);p=(a+b+c)/2;s=sqrt(p*(p-a)*(p-c)*(p-b));

#include"stdio.h"#include"time.h"main(){inta[100],i,t,x,k=0;intm=1,n=100;printf("该数组元素有：\n");srand((