编写程序,将一个三位数逆序输出,比如,原三位数为123,新数为321.
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参考:http://hi.baidu.com/%D7%F6%B6%F8%C2%DB%B5%C0/blog/item/5522a1674310773caa184c64.html
#includeintisp(intn){inti=2;for(i=2;i
Function Exchange(ByVal num As Integer) If num
1#include"stdio.h"main(){intn,i;scanf("%d",&n);printf("%d",n/100+n%100/10+n%10);system("PAUSE");}2#i
#includechars[20],t;intmain(){scanf("%s",s);if(s[2]>s[0]){t=s[0];s[0]=s[2];s[2]=t;}printf("%s\n",s);
scanf("%d,%d,%d,&a,&b,&c");改成scanf("%d,%d,%d“,&a,&b,&c);printf("thelargerstnumberis%d\n,max");改成prin
#include<stdio.h>int main(void){ int n,count = 0;&n
是C语言的吗?#includevoidmain(){ints,l,n,m,k;printf("请输入一个三位数的整数:");scanf("%d",&s);l=s/100;n=(s/10)%10;m=s
#includevoidmain(){inta,b,c,d,t,m,n;printf("输入三个整数:\n");scanf("%d%d%d",&a,&b,&c);d=a+2*b+3*c;printf(
#include"stdio.h"voidmain(){\x09inta;\x09intb[3];\x09intcount=0;\x09printf("请输入一个数");\x09scanf("%d",
算法分析:把输入的三位数分解(百,十,个);再交换个位和百位就可行了.#include{intn,a,b,c,x;printf("请输入一个三位数:\n");scanf("%d",&n);a=n/10
intmain(){intn,n1,n2;cin>>n1;n2=n1%100;n1=n1/100;n=n1;n2=n2%10;n1=n1/10;n=n+10*n1+100*n2;returnn;}
#includemain(){intn,i;inta[10];printf("请输入个数n:");scanf("%d",&n);for(i=0;i=0;i--)printf("%d\t",a[i]);
publicclassFactorial{privateintresult=1;publicintfactorial(intnumber){if(number==1)returnresult;else
#include "stdio.h"#define ROW 14#define COL 12int main(){ch
#include<stdio.h>int main(){int n,s=0;scanf("%d",&n);while(n){s=
programj;vara,b,c,m,n:integer;beginreadln(m);a:=mdiv100;b:=(mdiv10)mod10;c:=mmod10;n:=c*100+b*10+a;w
#include#includeboolCheck(intn){if(n
你好.看代码#includevoidsort(int*a,int*b,int*c){intt;t=*a;*a=*a>*b?*a:*b;*b=*a>*b?*b:t;t=*a;*a=*a>*c?*a:*c
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){chari,ci,j,n,ch;printf("请输入菱形中心数.