编写程序,列举出前n项fibonacci数,要求每显示5项换一行输出-搜答案-拍题作业网

#includevoidmain(){floatsum=0.0;intn=0,sign=-1;scanf("%d",&n);for(floati=1;i

1.用dowhile循环写出计算100以内奇数和的程序clearsettalkoffs=0i=1dowhilei

#includeintmain(){intn,i,sum;scanf("%d",&n);sum=0;for(i=1;i

PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli

main(){inti,n,s=1,f[]={0,1,1};printf("Pleaseinputthenumberofterms:");scanf("%d",&n);if(n==0){s=0;f[2

什么时候要?再问：呵呵，什么时候这个小问题解决了就不要了啊!·~~~~~~~~~~~~~~啊~开玩笑的啊，呵呵，对这个程序，当n一定时（比如20,30,40等等）我都可以写出来，但是.......当n

/*1-2/3+3/5-4/7+5/9-6/11+.的前n项之和*/intmain(intargc,char*argv[]){intnum_n=1;inti=0;doubleresult=0.0;pr

intmain()doubleresult;inti;intn;scanf("%d\n",n);for(i=1;i

编写程序从n（20

c语言编写#includevoidmain(){intn,max,min,avg,sum,count=0;max=20;min=20;sum=0;for(n=20;nmax)max=n;if(n

用心思考,用手写就能写出来

sum=sum+1/(5*i+1);这一句,1/(5*i+1)的值是整数的,所以它一直是0这样好像可以sum=sum+(double)1/(5*i+1);

for(inti=1;i

#include"stdafx.h"voidmain(){ints=0;for(intn=1;n

“i=1”---->"i==1","i=2"------>"i==2"

#includeintFibonacci(intn){return(n==0||n==1)?n:Fibonacci(n-1)+Fibonacci(n-2);}intmain(){intn=0,num=

longn=0;for(inti=1;i

1.dimi,jasIntegerfori=1to20j=j+i*(i+1)*(i+2)nextimsgboxj

#include <stdio.h>long u, v;void addrat(int, int);void lowterm()

#include"stdio.h"voidmain(){floatans=0;inti;for(i=1;i

#includeintsum(intn){intj,s=0;for(j=1;j