作业帮编写函数fun,求1到m之间的偶数之积
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 16:26:52
floatfun(intm){ inti,j,count,iszishu; floatsum; &
intfun(intn){intm=1,sum=0,i,j;for(i=1;i
PrivateSubfun()ifimod2=0thenforx=itoastep2s=s*xnextxelseforx=(i+1)toastep2thens=s*xnextxendif试试看行不行吧
fun(){for(inti=1;i
voidfun(intm,int*k,intxx[]){inti,j=0;*k=0;for(i=2;i
#include#includeintprime(inti){intk;for(k=2;k
double fun(int n){\x09int i,j;\x09double s=0;\x09for(i=3;i<=n;i++)\x09{\x09\x
#include#includedoublefun(intn){intm=3,i;doubles=0;while(m
PrivateFunctionSumA(ByValaAsInteger)AsLongDimiAsInteger,NAsIntegerFori=500To600IfiModa=0ThenN=N+iNex
上面的错了应该是intfun(){inti,sum=1;for(i=1;i
#include#includevoidswap(intc[],intlen){inti=0;inttmp;for(;i{tmp=c[i];c[i]=c[len];c[len]=tmp;}}intmu
#includeinta[50];intfun(intm){intn=0;for(inti=1;i
Functions(ByValaAsInteger,ByValbAsInteger)AsIntegerDimiAsIntegerFori=1To1000IfiModa=0AndiModb=0Thens
#include#include#includeintisprime(intn){inti;for(i=2;i
用这肯定可以intfun(intm){for(inti=m-1;i>1;i--){intj;booleanisPrime=true;for(j=2;jif(i%j==0){isPrime=false;
#include#includefloatfun(inta,intb){floatc;c=sqrt(a)+sqrt(b);returnc;}intmain(){inta=12,b=20;floatc;
functionfun(d,h){if(d
#includeintfun(intM,inta[]){intn=0;inti;for(i=1;i{if(i%7==0||i%11==0){a[n]=i;n++;}}returnn;}intmain(
#includeusingnamespacestd;intmain(){intn,m,num=0,a,b,c;cin>>m>>n;while(m0){a=m%10;s=s+a;m=m/10;}m=c;
intfun(w){intsum=0;for(inti=1;i