编写函数,计算s=6! 10

#include#includedoublefun(intn){inti;doublex=1.0,sum=x;if(n==0)return0.0;for(i=2;i

#includedoublefun(inti){intj;doublesum=1;for(j=1;j

main(){ints;s=getfactorial(6)+getfactorial(10)+getfactorial(20)printf("s=%d",s);}intgetfactorial(int

用递归函数#include#includeintinv(intx);main(){intsum=0,i;for(i=1;i

inti,j;\x09intn,sum=0;\x09inttemp=1;\x09scanf("%d",&n);\x09for(i=1;i

PrivateSubCommand1_click()DimnAsIntegern=100Printf(n)EndSubFunctionf(n)Fori=1Tonf=f+1/iNextiEndFunct

vars:real;n:longint;functionjc(x:longint):longint;vari:longint;beginjc:=1;fori:=2toxdojc:=jc*i;end;f

#includeintmain(void){intn;inti,j;floatsum=1.0;floatdex=1.0;printf("输入一个数：");scanf("%d",&n);for(i=2;

#include#includeusingnamespacestd;doubles(intn);doublesumi(intn);intmain(){cout

#includeusingnamespacestd;voidjishu(intn){intk=1;inta=1;doubles=0;for(inti=0;i

#include "stdio.h"double fact(int n)//求n的阶乘,用double的目的是为了增加精度{  &

#includedoublesum(doublex,intn){\x05doubles=1;\x05inti;\x05doublet=1;\x05doublea=1;\x05for(i=1;i再问：以

我用php语言写的.分两个步骤,一个是计算每个节点的值,用递归算法.一个是节点的累加,用循环算法.这么好的答案,不给分,没良心.再问：谢谢了，我没说清楚，我现在学的是c++语言，真的很感谢

这个已经帮你做完了哈

publicclassTest{publicstaticvoidmain(String[]args){ints=0;intn=1;for(inti=0;i

#include"stdio.h"intfact(inta){inti,s=1;for(i=1;i

原型：在TC2.0中原型为externfloatpow(floatx,floaty);而在VC6.0中原型为doublepow(doublex,doubley);头文件：math.h功能：计算x的y次

#include#includedoublefun(intn)//计算1!+2!+3!+.+n!,并赋值给fun{inti;doubles=0,t=1;for(i=1;i

;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX

CLEARSETTALKOffs1=0forn=1to10s1=s1+jc(n)next"1!+2!+3!+.+10!=",s1FUNCTIONjcPARAMETERSis=1FORj=1TOis=s