编写函数,求两个整数的最小公倍数.

intadd2(inta,intb){return(a+b);}voidmain(){inta,b,c=0;couta>>b>>c;cout

(1)intmain(){inta,b,c;cin>>a>>b>>c;returna+b+c;}(2)intget_sum(intx,inty){returnx+y;}intmain(){inta,b

#includemain(){inta,c,b,d;scanf("%d%d",a,b);c=a+b;d=a*b;printf("%d%d",c,d);}再问：采用函数的方法再答：先输入两个数，然后执行

这个简单：#includeusingnamespacestd;intHe(intx,inty){intz;z=x+y;returnz;}intCha(intx,inty){intz;z=x-y;ret

#include"stdafx.h"#includeintsct(intm,intn){inttemp,a,b;if(m>y;g=sct(x,y);cout再问：是fun函数吗？测试用的主函数

#include<stdio.h>int getmax(int a,int b){      re

static void Main(string[] args){    //声明变量    

#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(

publicintmax(inta,intb){returna>b?a:b;}publicdoublemax(doublea,doubleb,doublec){doublet=a>b?a:b;retu

楼主你好,这是源程序,是用辗转相除法写的#includeintmax(intp_a,intp_b){\x09if(p_b==0)\x09\x09returnp_a;\x09else\x09\x09re

intmax_common_divisor(inta,intb){//最大公约数intlarge_num,small_num,r;if(a>b){large_num=a;small_num=b;}el

#includeintmaxY(intm,intn){inti;for(i=n;i>0;i--)if(m%i==0&&n%i==0)break;return(i);}intminB(intm,intn

#includevoidmain(){inthcf(int,int);intlcd(int,int,int);intu,v,h,l;scanf("%d,%d",&u,&v);h=hcf(u,v);pr

#include/*C语言*/intmaxNum(inta,intb){return(a>b?a:b);}voidmain(){inta,b,max;printf("Entertwonumbers!\

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#includeusingnamespacestd;voidmain(){inta=0,b=0;cin>>a>>b;cout

#includevoidmain(){inta,b,sum=0;printf("请输入两个整数：");//将两个改成n个就好了scanf("%d%d",&a,&b);sum=a+b;printf("%

①#includeinthcf(inta,intb){\x09intc;\x09while(b){c=b;b=a%b;a=c;}\x09returna;}intlcd(inta,intb,intc){

我只会MATLAB,假设数组记为x,数组中元素各不相同[a,b]=max(x);%a是最大值,b是最大值的下标,即序号x(b)=[];%删除x的最大值次大值=max(x);%次小值类似[a,b]=mi

完整程序如下：#includefun(intx,inty){intr;if(x>y){x=x;y=y;}r=x;x=y;y=r;r=x%y;while(r!=0){x=y;y=r;r=x%y;}ret