作业帮编写一个程序,计算s=1! 2! 3! - n!.其中n由输入决定.
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 22:50:25
inta,n;doublesum=0;scanf("%d%d",&a,&n);for(sum=a,i=2;i
privatesubform_click()dimnaslong,snaslongn=inputbox("请输入n")fori=0tonsn=sn+2*i+1nextmsgbox"1+3+5+...(
s=0k=1whilei
publicclassSum{publicstaticintsum(){intj=0;for(inti=1;i
inti,j;\x09intn,sum=0;\x09inttemp=1;\x09scanf("%d",&n);\x09for(i=1;i
#includeintmain(void){intn;inti,j;floatsum=1.0;floatdex=1.0;printf("输入一个数：");scanf("%d",&n);for(i=2;
#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i
VB程序PrivateSubCommand1_Click()Dima,iAsIntegeri=1Whilei<50s=s+(i+1)/ii=i+1WendPrint"s=";sEndSu
用你那个问题的格式：reada,nt←as←0forifrom1tons←s+tt←t*10+aendforprintsend
s=0k=0fori=1to100s=s+iifi%2=0k=k+iendifendfor?"s=1+2+3++100=",s?"1-100的偶数和：",k
n!=n*(n-1)*(n-2)*...*2*1的意思就是n!等于前n个正整数相乘.不是楼主所说的3!=3*(3-1)*(3-2)*(3-3)*3*2*1.3!=3*2*1（其实就是1*2*3=3!）
inti,S=0;for(i=1;i
希望能帮到你.#include"stdio.h"intmain(){inti,j,n,s,temp;printf("请输入n的值:");scanf("%d",&n);for(i=1;i
publicclassTest{publicstaticvoidmain(String[]args){ints=0;intn=1;for(inti=0;i
#includeusingnamespacestd;voidmain(){intn,t=0;longsum=0;cin>>n;for(inti=1;i
第一种：s=0i=1dowhilei
用什么语言啊?如果是java的话就如下：ints=0；for（inti=1；i
;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX
CLEARSETTALKOffs1=0forn=1to10s1=s1+jc(n)next"1!+2!+3!+.+10!=",s1FUNCTIONjcPARAMETERSis=1FORj=1TOis=s
#includeintmain(){inti,s=0;for(i=1;i