编写一个函数,输出m的全部因子-搜答案-拍题作业网

publicclassClient{publicstaticvoidmain(String[]args){factors(120);factors(1200);factors(349);factors

functionmm(A,B)s=size(A);h=s(1);w=s(2);C=zeros(h,h);fori=1:hforj=1:hform=1:wC(i,j)=C(i,j)+A(i,m)*B(m

#include#include#include#includeusingnamespacestd;//计算num内的所有素数（不包括num）voidCalcPrimes(intnum,vector&

下面的我测试过了voidfoo(intn){inti;for(i=2;i

#include"stdio.h"#include"conio.h"#include?main(){intx,i;printf("输入一个正整数:\n");scanf("%d",&x);for(i=1

#includemain(){\x05intm,n;\x05ints=1;\x05intpower(inta,intb);\x05printf("inputmn(m^n):\n");\x05scanf

main{inti=2,n,s=0;printf("请输入n：")；scanf（“d%”,&n）；for（i

Dimn%,cs,i%n=Text1cs="1":i=2DoIfnModi=0Thenn=n/i:cs=cs&"×"&iElsei=i+1EndIfLoopWhileiOptionExplicitPr

/*打印所有水仙花数*/#include"stdio.h"#includevoidmain(){inti,j,k,sum;for(i=1;i

给你两种答案选择：（都是自己编的,而且经过VC测试的!）方法一：#includevoidmain(){inti,a,b=0;scanf("%d",&a);if(a==1)a++;for(i=0;i

function [ s ] = solve_area( a,b,c ) p=(a+b+c)./2;&nbs

首先你那个a[i]=a[i]*(n-j)/j公式有点问题吧,这样会输出全是1的啊...如果还是按照你这样可以改成如下代码：#include"stdafx.h"#include#include#incl

很基础的,楼主要好好学习啊#include#includevoidmain(){inti;scanf("%d",&i);for(intj=1;j

#include"stdio.h"intfact(inta){inti,s=1;for(i=1;i

function[a,b,c,d]=ff(A)a=max(A);b=min(A);c=mean(A);d=length(A);end

敢问楼主你是想找因子个数还是要输出所有奇数呢?你自己都说不清楚别人怎么帮你呢.

vari,n:longint;functionys(x:longint):longint;vari:longint;beginys:=0;fori:=1toxdiv2doifxmodi=0thenys

intfun(intn){inti,m=1;for(i=1;i

#includeintis_prime(intn){inti=0;for(i=2;i*i

//今天被百度吞了4份代码,上帝保佑这个别被吞了,哥的分数啊.#includeintmain(){intn,i,j;scanf("%d",&n);for(i=1;i