log2根号5.log3

(log34+log38)(log23+log29)+(log3根号2)(log97)/[(log1/37)(log三次根号48)]=(5lg32)(3lg32)+[9(lg23)(lg37)/4]/

(log25+log4125)log32/log根号35=(log25+log4125)log32/log325=(log25+log4125)log252=(log25+log25根号5)log25

(log2(5)+log4(125))(log3(2)/log√3(5))=(log2(5)+3/2log2(5))(log3(2)/2log3(5))=5/2log2(5)*1/2log5(2)=5

log3根号27+lg25+lg4+log24+(-2.5)0的平方＝(3/2)log₃3+lg100+2log₂2+(-2.5)º=3/2+2+2+1=13/2

这么看log2(根号3）=0.5log2(3)log3(根号2）=0.5log3(2)2的多少次方等于3呢,肯定大于13的多少次方等于2呢,肯定小于1所以log2(根号3）>log3(根号2）

原式=lg25/lg4-2lg10/lg4+lg9/lg2×lg√5/lg3×lg2/lg5=(2lg5)/(2lg2)-2/(2lg2)+(2lg3)/lg2×(½lg5)/lg3×lg2

答案是1.要用到换底公式logA（B）=lnB/lnA那么原式=（ln9/ln2）*（ln(根号5）/ln3)*(ln5/ln2)=2ln3/ln2*(1/2ln5)/ln3)*ln5/ln2你自己在

log4(log3(log2512)))=log4(log39))=log42=1/2再问：是根号下呀而且是根号里面的根号共有3个根号再答：log4(√log3(√log2512)))=log4(√l

log3根号27+lg25+lg4+7的log2幂+（-9.8）º=3/2+lg100+7^0.3010+1=3/2+2+1.8+1=6.3再问：7^0.3010怎么算得1.8再答：7^0.

log2(3)+log3(5)+log3(2)=log2(3)+log3(10)=4.2429387700296再问：=1g3/1g2+(lg5+lg2)lg3这个式子最后那个lg3原来是分母，，怎么

原式=-(27/8)^3＋1-1/9*log6^36=-(27/8)^3＋1-2/9=-(27/8)^3＋7/9.再问：log2^9*log3^4=log6^36？怎么算的？有什么依据？

原式=（log2(5)+(3/2)log2(5))×log3(2)/(2log3(5))=(5/2)log2(5)))×(1/2)log5(2)=5/4

log3（log2（log3x））≥0log2(log3x)≥1log3x≥2x≥9

没有错...换底公式的运用于逆运用.log(2)(3)xlog(3)(7)=ln3xln7/ln2xln3=ln7/ln2=log(2)(7)

利用公式lga^b=blga知：lg25=2lg5,lg9=2lg3,lg2倍根号2=(3/2)*lg2log2^25*log3^2倍根号2*log5^9（利用loga^b=lga/lgb,化成同底形

=log25*log581*log34+ln√e=log(2)5x4log(5)3x2log(3)2+1/2lne=8[log(3)5/log(3)2]xlog(5)3xlog(3)2+1/2=8lo

log2^5*log3^2倍根号2*log5^9=lg5*lg2倍根号2*lg9/(lg2*lg3*lg5)=3*lg5*lg2*lg3/(lg2*lg3*lg5)=3再问：log2^25*log3^

=1+1/2-3/2=0再问：你。。。求具体点。再答：(log3,4+log9,4)log4,3—log2,2根号2=log34×log43+log94×log43-log22^(3/2)=lg4/l

=log2√3,c=log3√22^b=√33^c=√2比较得b>c

(log3^4+log5^2)(log2^9+log2^根号3)=(lg4/lg3+lg2/lg5)(lg9/lg2+lg根号3/lg2)=(2lg2*lg5+lg2*lg3)/lg3*lg5*(lg