log2更号2除4

log2(4^x+4)=x+log2(2^(x+1)-3)log2(4^x+4)=log2(2^x)+log2(2^(x+1)-3)log2(4^x+4)=log2[2^x(2^(x+1)-3)]4^

log2(4^x+4)=log2(2^x)+log2[2^(x+1)-3]令2^x=a4^x=a²2^(x+1)=2alog2(a²+4)=log2(a)+log2(2a-3)lo

log2^(4^x+4)=x+log2^[2^(x+1)-3]log2^(4^x+4)-log2^[2^(x+1)-3]=xlog2[(4^x+4)/(2^(x+1)-3)]=x(4^x+4)/(2^

令a=log2(5)则log2(1/5)=-log2(5)=-a且5>2²,所以a>2a-2>0原式=√(a²-4a+4)-a=√(a-2)²-a=|a-2|-a=a-2

4根号2是2^(5/2)原式=log8(5/2)=log2(5/2)/log28=(log25-1)/3这才是正确答案,呵呵

log(2)4x=log(2)(2×2x）=log(2)2+log(2)2x=log(2)2x+1记log(2)2x=t,因为1/4≤x≤4所以-1≤t≤3原函数变形为f(t)=t²+t（-

log23+log23=2log23log23乘以log23等于2log23这个是错解但是对于高中对数的一般乘法还没有学不用掌握只需掌握加减法等即可再答：哪里不懂的话请追问理解的话给个采纳哦谢了再问：

log2[log4(log3x)]=0log4(log3x)=1log3x=4x=3^4=81同理log5(log2y)=1log2y=5y=32所以原式=4×9-2=34

log2SQR(7/48)+log212-1/2log248=0.5log27+0.5log248+log212-1/2log248=0.5log27+log212=log21008

log2(√2/2)·log2（√2/4）=(log2√2-log22)(log2√2-log24)=(1/2-1)(1/2-2)=(-1/2)(-3/2)=3/4

log2(4^x+4)=log2(2^x)+log2[2^(x+1)-3]令2^x=a4^x=a²2^(x+1)=2alog2(a²+4)=log2(a)+log2(2a-3)lo

=√(log23-2)²-log23=2-log23-log23=2-2log23选B再问：为啥变成了2-log23再答：你那一步不懂再问：第二步括号里是不是因为log23比2小所以变成2-

log(2,9)=log(2,3^2)=2log(2,3)log(2,8)=log(2,2^3)=3log(2,2)=3所以(log2,9)/(log2,8)=2/3(log2,3)

log2√(7/48)+log212-1/2log242=log2√(7/48)+log2(12)-log2√42=log2√(7/48)*12/√42=log2√7*144/48*42=log2√(

设t=log2(2^x-1)则log2(2^(x+2)-4）=2+t原式=t*（2+t）=3t=-3ort=1log2(2^x-1)=-32^x-1=1/82^x=9/8x=2log2(3)-3log

log25/4+log25=log25/4×5=log24=2

log2(x-4)²

(log3^4+log5^2)(log2^9+log2^根号3)=(lg4/lg3+lg2/lg5)(lg9/lg2+lg根号3/lg2)=(2lg2*lg5+lg2*lg3)/lg3*lg5*(lg

由题意可知2>1且log2（4x+3-x^2）>log2（4x-2）所以有4+3X-X^2>4X-2解得-30综上所述X解集为（1/2,2）