Java程序输出分别四位数

怕越界,改成字符串来接收输入的值了,简单代码如下：#include<stdio.h>#include<string.h>//判断字符串中是否为四位数.boolIs4WeiShu

publicclassPrintUpperChar{publicstaticvoidmain(String[]args){for(charM='Z';M>='A';M--){System.out.pr

importjava.io.*;classSEV{publicstaticvoidmain(String[]args)throwsIOException{intmax,min;doublesh;Inp

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

#includeusingnamespacestd;voidmain(){inta[4];cout再问：还是有好几个错误再答：#includeusingnamespacestd;voidmain(

publicclassTest{publicstaticvoidmain(String[]args){intsum=0;inti=2;while(i

按照你的要求写的如下代码,精短而高效,可以直接运行publicclassLuck{\x09publicstaticvoidmain(String[]args){\x09\x09intcount=123

publicstaticvoidmain(String[]arg){intk=0;intm=0;System.out.println("输入一个四位数");Scannerinput=newScanne

#includevoidmain(){inta[9][9],i,j,n;scanf("%d",&n);for(i=0;i

#includeintmain(){intn,m;scanf("%d",&n);m=0;while(n>0){m=m*10+n%10;n/=10;}printf("%d\n",m);return0;}

importjava.util.Scanner;publicclassEncpryt{publicEncpryt(){Scannerscan=newScanner(System.in);System.

#include#includeintmain(){longintnum;intindiv,ten,hundred,thousand,ten_thousand,place;printf("intput

除非你自定义函数,不然是不大可能的

#include<stdio.h>int main(){int n,s=0;scanf("%d",&n);while(n){s=

intnum=4568;intshiwei=0,baiwei=0,qianwei=0,gewei=0;qianwei=num/1000;baiwei=(num%1000)/100;shiwei=(nu

楼上说没错,while(X)是先进行X判断然后再执行{语句体},而do..while则是先执行do{语句体},再判断while(X),这样会导致do..while比while执行语句体的次数多一次再问

#includeintmain(){intn=0;inti=0;intd[4]={0};printf("Inputanum(-99999999):");scanf("%5d",&n);n%=10000

publicclassTest{publicstaticvoidmain(String[]args){for(inti=1;i

作为字符串形式读入比用整形读入好处理,而且数的位数不受限制（整型有数值超界问题）#includevoidmain(){chars[80];//最长80位数字inti,L;printf("pleasei