java从键盘输入长和宽计算周长和面积

importjava.util.Scanner;publicclassDemo{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

其实这是很容易的一个题的,不知道你是只要代码还是要解决过程,代码给你贴上,我测试过,能正常运行（在eclipse下,如果你要直接用dos编译运行的话,要改）packagecom;importjava.

publicstaticvoidprintNum(intn){for(inti=2;ij){if(i%j==0){m++;}}else{break;}}if(m<1){System.out.print

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

本人初学,答的不好的地方请见谅,程序代码如下：importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs

#includeintmain(){doublewidth;doubleheight;printf("请输入矩形的长：");scanf("%lf%*c",&height);printf("请输入矩形的

packagea1;importjava.util.Scanner;publicclassTest1{publicstaticfloatzhouchang(floatx,floaty){return2

importjava.util.Scanner;publicclassCircle{    publicstaticvoidmain(String[]args)

如图：

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

*vfp中计算n（从键盘输入的正整数）个实数（从键盘输入）去掉其中最大数和最小数之后的平均值的程序怎么写CLEARINPUT"输入共N个(正整数)个数字："TOnNDIMENSIONsz(nN)INP

//m与n的值不能太大,且用空格分隔.如：53#includeintfun(intn){\x09if(n==0||n==1)return1;\x09elsereturnn*fun(n-1);}void

BufferedReaderbuf=newBufferedReader(newInputStreamReader(System.in));System.out.print("请输入时间(注意格式必须为

调出来了：int[]b=newint[n];这个语句应该是上面的这个,要申请n个空间,不是n-1,否则会数组下标越界.运行后,先输入一个整数n,表示下面还要输入整数的个数,然后在输入n个整数,求这n个

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs[]){doublep,s,l,r;Strin

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S