java从键盘输入三角形的三边长,判断出这三边能否构成三角形

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

#include#includemain(){floata,b,c,p;doubleS;printf("请输入三边长度(如3,4,5)：");//注意逗号是西文的scanf("%f,%f,%f",&a

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

本人初学,答的不好的地方请见谅,程序代码如下：importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs

#include#includemain(){floata,b,c,x,y,z;floatd;doubleS;while(1){printf("请输入三角形三边的边长数：");pri

packagea1;importjava.util.Scanner;publicclassTest1{publicstaticfloatzhouchang(floatx,floaty){return2

importjava.util.Scanner;publicclassCircle{    publicstaticvoidmain(String[]args)

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

//给出三角形的三个边长a,b,c求三角形的面积//用海伦公式来计算三角形的面积p=(a+b+c)/2,S=根号下{p(p-a)(p-b)(p-c)}#include#includeintmain(v

判断从键盘输入的三个数能否构成三角形.如果是特殊的三角形（如等边、等腰、直角,等腰直角）需要能判断出来.

packageABC;importjava.io.*;publicclassdistantmoon{publicstaticvoidmain(String[]s)throwsException{

PrivateSubCommand1_Click()a=Val(InputBox("输入a的长"))b=Val(InputBox("输入b的长"))c=Val(InputBox("输入c的长"))If

PrivateSubCommand1_Click()a=Val(InputBox("输入a的长"))b=Val(InputBox("输入b的长"))c=Val(InputBox("输入c的长"))If

输入A,B,CA+B大于C且A-B小于C同时满足,输出若A^2+B^2=C^2或A^2+C^2=B^2或B^2+C^2=A^2(直角三角形其他的略面积,则要用海伦公式,不太好写出来,可以去查别浪费资源

importjava.util.Scanner;publicclassTest01{publicstaticvoidmain(String[]args){Scannerscan=newScanner(

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望

#include#includevoidmain(){floata,b,c,t,p,s;printf("请输入三边的长度\n");scanf("%f%f%f",&a,&b,&c);if(a>b){t=

importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs[]){doublep,s,l,r;Strin

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S