JAVA从键盘输入三个整数,分别计算它们的累加值与平均数.

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

2L你好夸张!把下面代码放到main()方法中Scanners=newScanner(System.in);System.out.println("请输入a的值：");inta=s.nextInt()

#includevoidmain(){\x09inta,b,c,min;\x09scanf("%d%d%d",&a,&b,&c);\x09min=a;\x09if(min>b)min=b;\x09if

#includevoidmain(){inta,b,c,t;printf("请输入3个数\n");scanf("%d%d%d",&a,&b,&c);if（b>c）{if(a再问：哥哥输入xyz为什么程

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

#include#includeintmain(){inttemp;inta,b,c;scanf("%d%d%d",&a,&b,&c);if(a>b)//保证a中存放最大值{temp=b;b=a;a=

importjava.util.*;publicclassCombination{publicstaticvoidmain(String[]args){VectortestData=newVector

判断从键盘输入的三个数能否构成三角形.如果是特殊的三角形（如等边、等腰、直角,等腰直角）需要能判断出来.

怎么个不对法?逻辑很正确,表达也严谨.有什么不对的现象说出来!再问：现象是输入1,2,3时输出的是2我刚刚把else那句删了程序就对了还是谢谢你

packageABC;importjava.io.*;publicclassdistantmoon{publicstaticvoidmain(String[]s)throwsException{

BufferedReaderbuf=newBufferedReader(newInputStreamReader(System.in));System.out.print("请输入时间(注意格式必须为

看看谁的效率高过我importjava.util.Arrays;importjava.util.InputMismatchException;importjava.util.Scanner;publi

#includevoidmain(){intx,y,z,sum,product,max,min;doubleaverage;coutx>>y>>z;sum=x+y+z;product=x*y*z;av

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望

#include"stdio.h"voidmain(){intx,y,z,t;scanf("%d%d%d",&x,&y,&z);if(x